A ball on a string travels once around a circle with a circumference of 2. 0 m. The tension in the string is 5. 0 n.
1 answer:
The work done by the ball on a string is 0J if a ball is travelling around as circle with a circumference of 2.0m
We know that circumference or perimeter of circle=2πr where r is the radius of the circle.
So, we have circumference=2m
Therefore,2πr=2
=>r=2/2π
=>r=(1/π) m
Now, we know very well that when a body moves a displacement dx under the action of force, some amount of work is done by the force on the body and that force is given by
W=
where F is defined as the force acting on the body
and dx is the displacement of the body.
On expanding the above formula, we get
=>W=Fdxcosθ where cosθ is the angle between the force and displacement of the body.
Since Tension is actually centripetal force which is acting along the center of the circle where ball displacement is in perpendicular direction to the tension.
It means angle between Tension and ball's displacement is 90°. So,cos90°=0
Therefore, W=Fdxcos90
=>W=0J.
Hence, amount of work done is 0J.
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(Complete question) is:
A ball on a string travels once around a circle with a circumference of 2. 0 m. The tension in the string is 5. 0 N. What amount of work done by the ball on the string?
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The figure of the problem is missing: find in attachment.
(a) 1.64 s
The ball follows a projectile motion path. The horizontal displacement is given by
where
is the initial speed
t is the time
is the angle below the horizontal
We can rewrite this equation as
(1)
The vertical displacement instead is given by
(2)
where
is the acceleration of gravity
Substituting (1) into (2),
We know that for t = time of flight, the horizontal displacement is
We also know that the vertical displacement is
Substituting everything into the equation, we can find the time of flight:
(b) 36.5 m/s
We can now find the initial speed directly by using the equation for the horizontal displacement:
where we have
x = 50.8 m
Substituting the time of flight,
t = 1.64 s
We find:
(c) 47.1 m/s at 48.8 degrees below the horizontal
As the ball follows a projectile motion, its horizontal velocity does not change, so its value remains equal to
The initial vertical velocity is instead
And it changes according to the equation
So at t = 1.64 s (when the ball hits the ground),
So the impact speed is:
While the direction is:
Answer:
Acceleration,
Explanation:
Given that,
Initial velocity, u = 20 m/s
Final velocity, v = 60 m/s
Time, t = 10 s
We need to find the acceleration of the car. It is equal to the change in velocity divided by time.
So, the acceleration of the car is .