The work done by the ball on a string is 0J if a ball is travelling around as circle with a circumference of 2.0m
We know that circumference or perimeter of circle=2πr where r is the radius of the circle.
So, we have circumference=2m
Therefore,2πr=2
=>r=2/2π
=>r=(1/π) m
Now, we know very well that when a body moves a displacement dx under the action of force, some amount of work is done by the force on the body and that force is given by
W=
where F is defined as the force acting on the body
and dx is the displacement of the body.
On expanding the above formula, we get
=>W=Fdxcosθ where cosθ is the angle between the force and displacement of the body.
Since Tension is actually centripetal force which is acting along the center of the circle where ball displacement is in perpendicular direction to the tension.
It means angle between Tension and ball's displacement is 90°. So,cos90°=0
Therefore, W=Fdxcos90
=>W=0J.
Hence, amount of work done is 0J.
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(Complete question) is:
A ball on a string travels once around a circle with a circumference of 2. 0 m. The tension in the string is 5. 0 N. What amount of work done by the ball on the string?
Answer:
The gas pressure is: 1.55 atm.
Explanation:
We need to use the equation that relate the variables given at the exercise (pressure, temperature and volume) from the ideal gas law formula, when the mass is constant we can reduce the expretion to
solving to P2 we get:
replace the values
.
a) Yes, if acceleration and velocity have opposite directions
b) Yes, if acceleration and velocity have same direction
Explanation:
a)
In order to answer this question, we have to keep in mind that both velocity and acceleration are vector quantities, so they have also a direction.
Acceleration is defined as the rate of change in velocity:
where
u is the initial velocity
v is the final velocity
t is the time elapsed
In this problem, the object is slowing down: this means that the magnitude of its velocity is decreasing, so
This means that the direction of the acceleration is opposite to the direction of the velocity. Then, the magnitude of the acceleration can be increasing (this will not affect the fact that the object will slow down, but it will affect only the rate at which the object is slowing down).
b)
In this case, the object is speeding up. This means that the magnitude of its velocity is increasing, so we have
In order for this to happen, it must be that the direction of the acceleration is the same as the direction of the velocity: therefore, this way, the magnitude of the velocity will be increasing (either in the positive or in the negative direction).
Then, the magnitude of the acceleration can be decreasing (this will not affect the fact that the object will speed up, but it will only affect the rate at which the object is speeding up).
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