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2 years ago

The measure of the force of gravity on an object, expressed as mass of the object times acceleration due to gravity is called

1 answer:

4 0

weight

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A 6.00-kg box is sliding to the right across the horizontal floor of an elevator. The coefficient of kinetic friction between th

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Answer: Kinetic frictional force = 23.76N

Explanation: Please see the attachments below

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3 years ago

A spring with a spring constant of 350 N/m pulls a door closed. How much work is done as the spring pulls the door at a constant

german

The work done to stretch the spring will be 112 J.

<h3>What is spring force?</h3>

The force required to extend or compress a spring by some distance scales linearly with respect to that distance is known as the spring force. Its formula is

F = kx

The given data in the problem is;

F is the spring force =?

K is the spring constant= 8.5 N/m

x is the length by which spring got stretched = 1.2m

The work is done to stretch the spring is;

$\rm W= \frac{1}{2} kx^2 \\\\ W=\frac{1}{2} \times 350 \times (0.850-0.050)^2 \\\\ W=0.5 \times 350 \times (0.80)^2 \\\\W=112 \ J$

To learn more about the spring force refer to the link;

brainly.com/question/4291098

#SPJ1

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2 years ago

We can use energy principles to make ____ predictions.

stira [4]

Compatible and speedy

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3 years ago

There isnt enough sanitidzer(alcohol)what solution to be replaced

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For me: WASH OUR HANDS REGULARLY

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2 years ago

A pair of slits separated by 1 mm, are illuminated with monochromatic light of wavelength 411 nm. The light falls on a screen 1.

Ilya [14]

Answer:

$t = 0.192 \mu m$

Explanation:

Path difference due to a transparent slab is given as

$\Delta x = (\mu - 1) t$

here we know that

$\mu = 1.79$

now total shift in the bright fringe is given as

$Shift = \frac{D(\mu - 1)t}{d}$

Also we know that the fringe width of maximum intensity is given as

$\delta x = \frac{\lambda D}{d}$

now we have

$\frac{D}{d} = \frac{\delta x}{\lambda}$

now the shift is given as

$Shift = \frac{(\mu - 1) t \delta x}{\lambda}$

given that the shift is

$Shift = 0.37 \delta x$

here we have

$0.37 \delta x = \frac{(\mu - 1) t \delta x}{\lambda}$

now plug in all values in it

$0.37 = \frac{(1.79 - 1) t}{411 \times 10^{-9}}$

$t = 0.192 \times 10^{-6} m$

$t = 0.192 \mu m$

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3 years ago