Answer: 107 grams
Explanation: got it right on the test
The m/z and relative abundance of the ions contributed to the peak at 21.876 min. The relative abundance will be 21.876%.
<h3>
What is relative abundance?</h3>
- The proportion of atoms with a particular atomic mass present in an element sample taken from a naturally occurring sample is known as the relative abundance of an isotope.
- When the relative abundances of an element's isotopes are multiplied by their atomic masses and the results are added up, the result is the element's average atomic mass, which is a weighted average.
- Chemists often divide the number of atoms in a particular isotope by the sum of the atoms in all the isotopes of that element, then multiply the result by 100 to determine the percent abundance of each isotope in a sample of that element.
To learn more about relative abundance with the given link
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<span>Quarks are present in protons and neutrons but not in electrons.</span>
The first thing you need to do is calculate the molar mass of C4H10. To do this, look at a periodic table for the atomic mass of carbon and hydrogen. For Hydrogen it's 1.008 amu. For Carbon its 12.01 amu. This means that a mole of hydrogen has a mass of 1.008 amu. So to calculate the molar mass of C4H10:
atomic mass of H * number of H atoms in one molecule + atomic mass of C * number of C atoms in one molecule
1.008 * 10 + 4 * 12.01
= 58.12 g
So one mole of C4H10 would have a mass of 58.12 g.
Now you were told to find the number of moles for 2.50 g, so you need to change 2.50g into moles
2.50g *1 mole/ 58.12 g = .043014 moles of C4H10
You know that for every mole of C4H10, there are 4 moles of Carbon
so
.043014 mole C4H10 * 4 mole C/1 mole C4H10 = .172 mol C
Now to find the number of atoms, use avogadros numbe5r
6.022 * 10^23 * .17 mol = 1.024 × 10^23 atoms your answer.The first thing you need to do is calculate the molar mass of C4H10. To do this, look at a periodic table for the atomic mass of carbon and hydrogen. For Hydrogen it's 1.008 amu. For Carbon its 12.01 amu. This means that a mole of hydrogen has a mass of 1.008 amu. So to calculate the molar mass of C4H10:
atomic mass of H * number of H atoms in one molecule + atomic mass of C * number of C atoms in one molecule
1.008 * 10 + 4 * 12.01
= 58.12 g
So one mole of C4H10 would have a mass of 58.12 g.
Now you were told to find the number of moles for 2.50 g, so you need to change 2.50g into moles
2.50g *1 mole/ 58.12 g = .043014 moles of C4H10
You know that for every mole of C4H10, there are 4 moles of Carbon
so
.043014 mole C4H10 * 4 mole C/1 mole C4H10 = .172 mol C
Now to find the number of atoms, use avogadros numbe5r
6.022 * 10^23 * .17 mol = 1.024 × 10^23 atoms your answer.
Hope it helps
Reaction between mercury (ii) sulfide with Calcium oxide is as shown;
4 HgS +4 CaO = 4 Hg + 3 CaS + CaSO4
The molar mass of HgS is 232.66 g/mol
The number of moles = 31.28/232.66
= 0.1344 moles
The mole ratio of HgS : CaO is 1: 1
Therefore, the number of moles of Calcium oxide is 0.1344 moles
1 mole of CaO Contains 56 g/mol
Thus, the mass of CaO is 56 g/mol
= 0.1344 moles × 56 g/mol
= 7.5264 g
