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2 years ago

3 examples of technology transfer pls

Engineering

2 answers:

OLEGan [10]2 years ago

3 0

Answer: electrical, mathematical, and geographical

Explanation: Yee

- Cash Nasty

slamgirl [31]2 years ago

3 0

Geographical,mathematical,electrical

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thermal energy is being added to steam at 475.8 kPa and 75% quality. determine the amount of thermal energy to be added to creat

eduard

Answer:

$q_{in} = 528.6\,\frac{kJ}{kg}$

Explanation:

Let assume that heating process occurs at constant pressure, the phenomenon is modelled by the use of the First Law of Thermodynamics:

$q_{in} = h_{g} - h_{mix}$

The specific enthalpies are:

Liquid-Vapor Mixture:

$h_{mix} = 2217.2\,\frac{kJ}{kg}$

Saturated Vapor:

$h_{g} = 2745.8\,\frac{kJ}{kg}$

The thermal energy per unit mass required to heat the steam is:

$q_{in} = 2745.8\,\frac{kJ}{kg} - 2217.2\,\frac{kJ}{kg}$

$q_{in} = 528.6\,\frac{kJ}{kg}$

7 0

3 years ago

Jelena is 26 and has worked in the service industry for most of her work history. She is willing to advance her education and tr

katrin2010 [14]

Customer service

Since she has reckless driving and her record, anything involving driving of some sorts mechanics as well won’t work well with her!! Hope this helps

8 0

2 years ago

A lake with an area of 525 [acre] was monitored during a one-month period. The average inflow was 30 [cfs] for the month and the

Alex73 [517]

Answer:

$\Delta S = 1581663.5ft^3$

Explanation:

We need to calculate the change in storage through the changes given,

That is,

$\Delta S = P+I-O-O_{seepage}-E$

Where the loss are representing by,

$P= Precipitation\\I= Inflow\\O= Outflow\\O_{Seepage}= Outflow by seepage\\E=Evaporation$

So calculating the values we have

$\Delta S = P+(I-0)-O_{seepage}-E$

$\Delta S = 4.25+ (30ft^3/s-27ft^3/s)-1.5in-6in$

The values inside the are parenthesis need to be konverted as I note here.

$(30days(24hr/1day)(3600s/1hr)(1acre.ft/43560ft^3)(1/525acres)(12in/1ft)$

That is,

$\Delta S = 0.83in\Delta S= (0.83in*1ft/12in)(525acres)\\\Delta S=36.31 acres.ft\\\Delta S=36.31acres.ft*(43560ft^3/acrees.ft)\\\Delta S = 1581663.5ft^3$