Question

internal pressure is 1.25 atm, and its volume is 2.50 L. If the balloon is taken to the bottom of the ocean (pressure = 95.0 atm), what would be its new volume?

Answer 1

Pressure and Volume are related by Boyle's Law as:

$P_{1}V_{1} = P_{2}V_{2}$

P1 = Initial pressure = 1.25 atm
V1 = Initial volume = 2.50 L
P2 = Pressure at ocean bottom = 95 atm
V2 = Volume at ocean bottom = x = ?

Using the values in the equation, we get

$1.25(2.5)=95x \\ \\ x=0.03 L$

This means, the volume at the bottom of the ocean will be 0.03 L. The volume is decreased due to increased pressure.