Draw the structure for each compound below:________. A) Propanedial B) 4-Phenylbutanal C) (S )-3-Phenylbutanal D) 3,3,5,5-Tetram
ethyl-4-heptanone E) (R )-3-Hydroxypentanal F) meta-Hydroxyacetophenone G) 2,4,6-Trinitrobenzaldehyde H) Tribromoacetaldehyde I) (3R,4R )-3,4-Dihydroxy-2-pentanone
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If one starts with 0.020 g of Mg, 0.0008 moles of H2 would be made if the reaction is complete.
Going by the balanced equation of reaction in the image, 1 mole of Mg will produce 1 mole of H2 in a complete reaction.
If 0.020 g of Mg is started with:
mole of Mg = mass/molar mass
= 0.020/24.3
= 0.0008 moles
Since the mole of Mg to H2 is 1:1, thus, 0.0008 moles of H2 will also be made from the reaction.
More on stoichiometry can be found here: brainly.com/question/9743981
