1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Yakvenalex [24]
3 years ago
9

The combustion reaction of propane is described by the reaction. c3h8 5o2 → 4h2o 3co2. how many moles of o2 are required to gene

rate 3 moles of co2
Chemistry
2 answers:
dmitriy555 [2]3 years ago
7 0
C₃H₈   +   5 O₂   →   4 H₂O   +   3 CO₂

mole ratio based on balance equation of  O₂   :   CO₂ i  s    5  :  3
                      C₃H₈   +   5 O₂   →   4 H₂O   +   3 CO₂

∴ if moles of CO₂  =  3 moles
  
then moles of O₂  = (3 moles ÷ 3) × 5
                             
                             =  <span>5 moles   </span>
Natali5045456 [20]3 years ago
6 0

Answer:

5 moles of O_{2} are required to generate 3 moles of CO_{2}

Explanation:

According to given balanced equation, 5 molecules of O_{2} reacts with 1 molecules of C_{3}H_{8} to produce 4 molecules of H_{2}O and 3 molecules of CO_{2}.

So, 5 molecules of O_{2} generate 3 molecules of CO_{2} or (5\times 6.023\times 10^{23}) molecules of O_{2} generate (3\times 6.023\times 10^{23}) molecules of CO_{2}

As 1 mol = 6.023\times 10^{23} molecules therefore  5 moles of O_{2} are required to generate 3 moles of CO_{2}

You might be interested in
Why is the energy supplied by the cooker greater than that calculated ?
TEA [102]

Answer:

Explanation:

Q1.

(a) 46 200

accept 46 000

allow 1 mark for correct substitution

ie 0.5 × 4200 × 22 provided no subsequent step

2

(b) Energy is used to heat the kettle.

[3]

Q2.

(a) (approximate same size particles as each other and as liquid and gas) touching

do not accept particles that overlap

regular arrangement (filling the square)

(b) condensing

(c) solid

(d) physical

(e) particles have more kinetic energy

particles move faster

(f) mass of the liquid

specific latent heat of evaporation

(g) 2 × 4 200 × 801

672 000 (J)

an answer of 672 000 (J) scores 2 marks

[11]

Q3.

(a) x-axis labelled and suitable scale

Page 12 of 13

points plotted correctly

allow 5 correctly plotted for 2 marks, 3−4

correctly plotted for 1 mark

allow ± ½ square

2

line of best fit

(b)

allow ecf from line of best fit in part (a)

0.075 (°C/s)

an answer of 0.075 (°C/s) scores 2 marks

(c) Δθ = 11.5 (°C)

a calculation using an incorrect temperature

scores max 3 marks

ΔE = 1.50 × 900 × 11.5

ΔE = 15 525 (J)

ΔE = 15.525 (kJ)

an answer of 15.525 (kJ) or 15.53 (kJ) or 15.5

(kJ) scores 4 marks

an answer of 15 525 (kJ) scores 3 marks

[10]

Q4.

(a) 80 °C

ΔE = 0.5 × 3400 × 80

ΔE = 136 000 (J)

an answer of 136 000 (J) scores 3 marks

(b) energy is dissipated into the surroundings

allow any correct description of wasted energy

(c) put a lid on the pan

allow any sensible practical suggestion

eg add salt to the water

Page 13 of 13

(d) efficiency = 300/500

efficiency = 0.6

an answer of 0.6 or 60% scores 2 marks

allow efficiency = 60%

an answer of 0.6 with a unit scores 1 mark

an answer of 60 without a unit scores 1 mark

7 0
2 years ago
Is nickel a compound
ELEN [110]

Answer:

No

Explanation:

5 0
2 years ago
Read 2 more answers
A serving of Cheez-Its releases 1.30 x 10^4 kcal (1 kcal = 4.18 kJ) when digested by your body. If this same amount of energy we
kondor19780726 [428]

Answer:

The final temperature is:- 7428571463.57 °C

Explanation:

The expression for the calculation of heat is shown below as:-

Q=m\times C\times \Delta T

Where,  

Q  is the heat absorbed/released

m is the mass

C is the specific heat capacity

\Delta T  is the temperature change

Thus, given that:-

Mass of water = 1.75 mg = 0.00175 g ( 1 g = 0.001 mg)

Specific heat of water = 4.18 J/g°C

Initial temperature = 35 °C

Final temperature = x °C

\Delta T=(x-35)\ ^0C/tex]&#10;Q = [tex]1.3\times 10^4 kcal

Also, 1 kcal = 4.18 kJ = 4.18\times 10^3 J

So, Q = 1.3\times 10^4\times 4.18\times 10^3 J = 54340000 J

So,  

54340000=0.00175\times 4.18\times (x-35)

0.00175\times \:4.18\left(x-35\right)=54340000

x-35=\frac{54340000}{0.007315}

x=7428571463.57

Thus, the final temperature is:- 7428571463.57 °C

3 0
2 years ago
Differentiate benzene and cyclohexane
slega [8]
<span>• Benzene has the formula of C6H<span>6 </span>whereas cyclohexane has the formula of C6H<span>12.
</span></span>
Benzene is an aromatic compound but cyclohexane is not aromatic.

Benzene is an unsaturated molecule, but cyclohexane is saturated.
<span>
Carbon atoms in the benzene ring have sp2 hybridization where carbon atoms in the cyclohexane have sp3 hybridization.</span>
 
Benzene has a planar structure whereas cyclohexane has chair conformations.<span>
</span>
5 0
2 years ago
What is the atomic mass of one mole of H? g/mole
Oksanka [162]
For one mole of hydrogen, H, the atomic mass is 1 g per mole. Hydrogen contains 1 proton and zero neuton. A neutral atom of hydrigen also contains 1 electron.
7 0
2 years ago
Read 2 more answers
Other questions:
  • A military jet cruising at an altitude of 12.0kmand speed of 1900./kmh burns fuel at the rate of 74.4/Lmin. How would you calcul
    5·1 answer
  • A 18.00 g candy bar is found to contain 11.00 g of sugar. How many mg of sugar does the candy bar contain ?
    11·1 answer
  • A 24.0 gram object has a volume of 6.0 mL. What is the density of the object?
    15·2 answers
  • How many grams of calcium would be a typical amount in a 60-kg adult?
    15·2 answers
  • What is the anion of the compound Cu(CH3COO)2?
    9·1 answer
  • Calculate the density of an<br> object with a mass of 20 g<br> and a volume of 2.3 mL.
    11·2 answers
  • chemistry A basketball is inflated to a pressure of 1.10 atm in a 28.0°C garage. What is the pressure of the basketball outside
    8·1 answer
  • We can also use the equation for enthalpy change for physical phase changes. Consider the phase change H2O(l) → H2O(g). Calculat
    15·2 answers
  • A solution of 0.2 M Sulfuric acid is titrated with a 0.2 M basic solution. In three to five sentences, explain how you can use t
    13·1 answer
  • What volume of carbon dioxide in liters could be generated at 0.96 atm and 362. K by the combustion of 228.85 grams of oxygen ga
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!