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mart [117]
3 years ago
11

GIVE REASON: 1.Trees catches fire2.We cannot put off fire due to electric shock by water​

Chemistry
2 answers:
Keith_Richards [23]3 years ago
8 0

1. The trees' large surface area and porous characteristic pulls in more oxygen that fuels fire. Often, trees are positioned near curtains, presents, furniture, or rugs, which can quickly catch fire too, spreading fire quickly throughout a home.

2. Water is a natural conductor of electricity and if you throw water on an electrical fire, you can get shocked or electrocuted. Also, water may enable to fire to spread by conducting electricity throughout the room and potentially igniting flammable materials.

kramer3 years ago
4 0

Explanation:

1. Under the influence of heat, wood produces easily substances that react eagerly with oxygen, leading to the high propensity of wood to ignite and burn.

2. Water is a natural conductor of electricity and if you throw water on an electrical fire, you can get shocked or electrocuted. Also, water may enable to fire to spread by conducting electricity throughout the room and potentially igniting flammable materials.

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aleksandrvk [35]

Answer:

Can I get my 50 points now?

Explanation:

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7 0
3 years ago
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Explain why atoms would gain or lose electrons in order to resemble the elements in the particular group you named above. Consid
posledela

Answer:

<em>The number of electrons in the outermost shell of an element is represented in the periodic table as the group number that element is situated in. ... the number of electrons in all shells of an element is represented in the periodic table as the element's atomic number.</em>

Explanation:

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6 0
2 years ago
Give the oxidation state of the metal species in each complex. ru(cn)(co)4 -
kogti [31]
The given complex ion is as follow,

                                              [Ru (CN) (CO)₄]⁻

Where;
            [ ]  =  Coordination Sphere

            Ru  =  Central Metal Atom  =  <span>Ruthenium

            CN  =  Cyanide Ligand

            CO  =  Carbonyl Ligand

The charge on Ru is calculated as follow,

                               Ru + (CN) + (CO)</span>₄  =  -1
Where;
            -1  =  overall charge on sphere

             0  =  Charge on neutral CO

            -1  =  Charge on CN

So, Putting values,


                               Ru + (-1) + (0)₄  =  -1

                               Ru - 1 + 0  =  -1

                               Ru - 1  =  -1

                               Ru  =  -1 + 1

                               Ru  =  0
Result:
          <span>Oxidation state of the metal species in each complex [Ru(CN)(CO)</span>₄]⁻ is zero.
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3 years ago
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Soloha48 [4]

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