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3 years ago

How many grams of sodium chloride could be produced from 41.3 L of chlorine gas?

Chemistry

1 answer:

babymother [125]3 years ago

6 0

Answer:

The grams of sodium chloride that will be made is 292.5 g. calculation. 2Na + Cl₂ → 2NaCl. step 1: calculate the moles of Na. moles = mass/molar mass. From periodic table the molar mass of Na = 23 g/mol. moles = 115 g/23 g / mol = 5 moles. Step 2 : use the mole ratio to determine the moles of NaCl. Na:NaCl is 2:2 = 1:1 therefore the moles of NaCl is also = 5 moles.

Explanation:

We know sodium is a very active metal and chlorine is also a very reactive non-metal. Usually, metals like to eliminate electrons and non-metals such as halogens like to accept electrons. Sodium readily eliminate its last shell electrons become Na+ cation and chlorine accepts that electron to form Cl-anion.

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If a yellow paint is to have 0.511% pbcro4 by mass, how many grams of chromite are needed per kilogram of paint?

Hitman42 [59]

Yellow paint has 0.511 % PbCrO4 by mass

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Moles of PbCrO4 = 5.11 g/ 323.19 g/mol

= 0.0158 moles

Moles of K2CrO4 also = 0.0158 moles

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Mass of FeCr2O4 (chromite) = 0.0079 moles * 223.83 g/mol

= 1.77 g

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2 years ago

If you transfer energy into two substances which one would melt first

I am Lyosha [343]

Answer:

The substance with a weaker molecular attraction

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2 years ago

Describe how the size of the sun compares to the sizes of the other stars.

alina1380 [7]

Answer:

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Explanation:

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3 years ago

Read 2 more answers

What is the difference between water and alcohol

Rudik [331]

Answer:

water is H2O having different structure than alcohol R-OH which means they have different properties too.

Explanation:

In water one oxygen atom is covalently bound with two hydrogen atoms while alcohol is an organic compound having Oh group attached to the carbon chain.

Other than liquid water can occur in solid form that is ice and in gaseous form that is vapors too while alcohol only present in liquid form.

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7 0

3 years ago

In this experiment we will be using a 0.05 M solution of HCl to determine the concentration of hydroxide (OH-) in a saturated so

gulaghasi [49]

<u>Answer:</u> The moles of hydroxide ions present in the sample is 0.0008 moles

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is HCl.

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is $Ca(OH)_2$

We are given:

$n_1=1\\M_1=0.05M\\V_1=16mL\\n_2=2\\M_2=?M\\V_2=36.0mL$

Putting values in above equation, we get:

$1\times 0.05\times 16=2\times M_2\times 36\\\\M_2=\frac{1\times 0.05\times 16}{2\times 36}=0.011M$

To calculate the moles of hydroxide ions, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}$

Molarity of solution = 0.011 M

Volume of solution = 36.0 mL

Putting values in above equation, we get:

$0.011=\frac{\text{Moles of }Ca(OH)_2\times 1000}{36}\\\\\text{Moles of }Ca(OH)_2=\frac{0.011\times 36}{1000}=0.0004mol$

1 mole of calcium hydroxide produces 1 mole of calcium ions and 2 moles of hydroxide ions.

Moles of hydroxide ions = (0.0004 × 2) = 0.0008 moles

Hence, the moles of hydroxide ions present in the sample is 0.0008 moles

8 0

3 years ago