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True [87]
3 years ago
9

Cathode ray tube experiments

Chemistry
1 answer:
PilotLPTM [1.2K]3 years ago
6 0

Answer:

Particles of the cathode rays are fundamental to all matter.

Matter contains negative charge and by inference positive charge.

There are subatomic size particles in an atom.

Cathode rays have mass.

Explanation:

  • <u>Radiation emitted from cathode was accelerated toward the anode in tubes.</u>

This means that the cathode rays which are travelling towards anode (positively charged) are negatively charged. Atom was considered to have subatomic particles.

C and D are correct.

  • <u>Cathode rays was observed to be same regardless of composition of cathode.</u>

This means that particles of cathode rays are fundamental to all the matter.

A is correct.

  • <u>The rays are influenced by the magnetic and electric field and also they move a light fan when placed inside the tube. </u>

It means that the cahrged particle has mass too.

D is correct.

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Commercial cold packs often contain solid NH4NO3 and a pouch of water. The temperature of the pack drops as the NH4NO3 dissolves
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Answer: b. \Delta H_{soln} is positive and \Delta S_{soln} is positive.

Explanation:-

As the temperature of the pack drops, the energy has been absorbed from the pack for dissolution of NH_4NO_3 in water. Thus as the energy has been absorbed in the reaction, the reaction is endothermic and the change in enthalpy i.e. \Delta H_{soln} is positive.

The entropy is the measure of degree of randomness. The entropy increases when the randomness increases and the entropy decreases when the randomness decreases. When a substance dissolves in water, it dissociate into ions and hence the randomness increases thus the change in entropy i.e. \Delta S_{soln}  is positive.

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3 years ago
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Verdich [7]
Third choice is correct. 
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3 years ago
The melting point of H₂O(s) is 0 °C. Would you expect the melting point of H₂S(s) to be 85 °C, 0 °C or -85 °C.? Justify your cho
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Answer:

-85 °C

Explanation:

O and S are in the same group( Group 16). Since S is below O it's atomic mass is higher than O. So molar mass of H2S is higher than H2O. The strength of Vanderwaal Interactions ( London dispersion forces) increases when the molar mass increases. However, only H2O can form H bonds with each other. This is because electronegativity of O is higher than S and therefore H in H2O has a higher partial positive charge than H of H2S.

H bond dominate among these 2 types of forces so the strength of attractions between molecules is higher in H2O than H2S. Therefore more energy should be supplied for H2O to break inter

molecular forces and convert from solid to liquid state than H2S. So mpt of H2O must be higher than that of H2S.

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