No' of molecules divide by avogadro number , 6×6.023×10^23 so (2.2×10^22)÷(6.023×10^23)
= 0.03653 moles
moles × Molar mass = mass
n×Mr=m
0.03653×40 = 1.46 grams
Answer:
36s^5
Explanation:
We have;
M2X3 (s)------> 2M^3+(aq) + 3X^2-(aq)
If [M^3+(aq)] = [X^2-(aq)] = s
We then have;
Ksp = (2s)^2 * (3s)^3
Ksp = 4s^2 * 9s^3
Ksp = 36s^5
Note that Ksp is known as the solubility product. It is an equilibrum equation that shows the solubility of a solute in water.
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Answer:
Explanation:
https://www.bbc.co.uk/bitesize/guides/zxgkp39/revision/3
Hope it helps
Mass of ammonium sulfate = 660.7 g
<h3>Further explanation</h3>
Given
3.01 x 10²⁴ molecules of ammonium sulfate
Required
mass
Solution
The mole is the number of particles(molecules, atoms, ions) contained in a substance
1 mol = 6.02.10²³ particles
Can be formulated
N=n x No
N = number of particles
n = mol
No = Avogadro's = 6.02.10²³
mol ammonium sulfate (NH₄)₂SO₄ :
n = N : No
n = 3.01 x 10²⁴ : 6.02 x 10²³
n = 5
mass ammonium sulfate :
= mol x MW
= 5 x 132,14 g/mol
= 660.7 g