Below is the structure of Benzilic Acid and IR spectrum. First common thumb rule for elucidating IR spectrum is to find a broad and intense signal between 1690-1800 cm⁻¹, If present! Then its for Carbonyl group. Secondly, watch for broad peak around 3400-3600 cm⁻¹, peak at this frequency is given by the -OH (Hydroxyl) group of Alcohols, andthe broadness is due to Association effect (Hydrogen bonding). Third, aif a wide band between 2500-3300 cm⁻¹ is present it shown -OH of carboxylic acid.
Result: Carbony Group = 1640 cm⁻¹
Carboxyl -OH Group = 2950 cm⁻¹
Alcohol -OH = 3400 cm⁻¹
Answer:
Radiation
Explanation:
<u>Radiation</u> travels in energy <u>waves</u>
Answer:
4054 kcal of heat is released during complete combustion of 354 g of octane.
Explanation:
Heat of combustion of 1 mol of octane is 
kcal
Molar mass of octane = 114.23 g/mol
We know, no. of moles = (mass)/(molar mass)
So, kcal of heat is released during complete combustion of 114.23 g of octane.
So, amount of heat is released during complete combustion of 354 g of octane = 
kcal = 4054 kcal
Hence 4054 kcal of heat is released during complete combustion of 354 g of octane.
Answer:chicken butt I need some points
Explanation:blm ✊✊✊✊ white lives don't
decameters - meters: multiply by 10
meters to meters: multiply by 1
centimeters to meters: divide by 100
millimeters to meters: divide by 1000
For the rows at the bottom:
hectometer row: 100, multiply by 100, 4500
decameter row: 10, multiply by 10, 450
meter row: 1, multiply by 1, 45
decimeter row: 0.1, divide by 10, 4.5
centimeter row: 0.01, divide by 100, 0.45
im guessing theres a millimeter row at the bottom:
millimeter row: 0.001, divide by 1000, 0.045
hope this helps!
