Answer:
tha mass of magnesium nitrate is 592g
Explanation:
from a balanced chemical equation
2HNO3 + Mg(OH)2→ Mg(NO3)2 + 2H2O
2 mol of nitric acid is equivalent to 1 mol of magnesium nitrate. then 8 mol of nitric acid will be equivalent to 4 mol of magnesium nitrate.
Answer : The mass of of water present in the jar is, 298.79 g
Solution : Given,
Mass of barium nitrate = 27 g
The solubility of barium nitrate at
is 9.02 gram per 100 ml of water.
As, 9.02 gram of barium nitrate present in 100 ml of water
So, 27 gram of barium nitrate present in
of water
The volume of water is 299.33 ml.
As we know that the density of water at
is 0.9982 g/ml
Now we have to calculate the mass of water.


Therefore, the mass of of water present in the jar is, 298.79 g
100 grams of solute would be present as 20% of 500 is 100
Explanation:
a particle smaller than an atom (e.g., a neutron) or a cluster of such particles (e.g., an alpha particle).