Question

Do you expect a strong chemical bond to have a higher or lower frequency than a weak bond?

Answer 1

Answer:

Higher frequency  

Explanation:

We can imagine a chemical bond between two atoms as if it were two balls connected by a spring.

According to Hooke's Law, the stretching frequency f is

$f = \dfrac{1}{2 \pi}\sqrt{ \dfrac {k}{\mu}}$

where µ is the reduced mass of the system

$\mu = \dfrac{m_{1} + m_{2}}{m_{1}m_{2} }$

The strength of the bond is analogous to k, the force constant of the spring. Then,

$f \propto \sqrt{k}$

Thus, the stronger the bond, the greater the frequency of vibration.