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schepotkina [342]
3 years ago
12

Is the star with the longest total lifetime Also the farthest from earth? Explain.

Physics
1 answer:
Stels [109]3 years ago
6 0
E) No. Ollie will shine for 30 Billion years but is only 10,000 LY from Earth.
F) No. Cosmo will shine for 3 Million years but is 10 Billion LY from Earth.
G) Yes. Ollie is only 10.000 LY away but will shine for 30 Billion years.
Ga) No. Stars such as Cosmo shine for 3 Million years.
Gb) If Cosmo was also 3 Million LY away we would see it now.
You might be interested in
A physics student standing on the edge of a cliff throws a stone vertically downward with an initial speed of 10 m/s. The instan
gizmo_the_mogwai [7]

Answer:

The velocity just before hitting the ground is v_f = 30 m/s

Explanation:

From the question we are told that

    The initial speed is  u = 10 m/s

    The final speed is  v = 30 \ m/s

From the equations of motion we have that

      v^2 =u^2 + 2as

Where s is the distance travelled which is the height of the cliff

  So making it the subject of the the formula  we have that

        s = \frac{v^2 - u^2 }{2a}

Where a is the acceleration due to gravity with a value  a = 9.8m/s^2

       So

                  s = \frac{30^2 - 10^2 }{2 * 9.8 }

                  s = 40.8 \ m

Now we are told that was through horizontally with a speed of

      v_x =10 m/s

Which implies that this would be its velocity horizontally through out the motion

    Now it final  velocity vertically can be mathematically evaluated as

            v_y = \sqrt{2as}

Substituting values

             v_y = \sqrt{(2 * 9.8 * 40.8)}

             v_y =  28.3 \ m/s

The resultant final velocity is mathematically evaluated as

       v_f = \sqrt{v_x^2 + v_y^2}

Substituting values

       v_f = \sqrt{10^2 + 28.3^2}

       v_f = 30 m/s

   

5 0
3 years ago
A racing car can complete a 900 m long lap in 15 s. What is the speed of the car?
Gemiola [76]

60 is the speed of the car

4 0
3 years ago
Read 2 more answers
Cart A, with a mass of 0.20 kg, travels on a horizontal air trackat 3.0m/s and hits cart B, which has a mass of 0.40 kg and is i
inysia [295]

Answer:

\large \boxed{\text{C. 2.3 m/s}}

Explanation:

Data:

m_{\text{A} } = \text{0.20 kg};\,v_{\text{Ai}} = \text{3.0 m/s}\\m_{\text{B} } = \text{0.40 kg};\,v_{\text{Bi}} = \text{2.0 m/s}\\

Calculation:

This is a perfectly inelastic collision.  The two carts stick together after the collision and move with a common final velocity.

The conservation of momentum equation is

\begin{array}{rcl}m_{\text{A}}v_{\text{Ai}} +m_{\text{B}} v_{\text{Bi}}&=&(m_{\text{A}}  + m_{\text{B}})v_{\text{f}}\\0.20\times 3.0 + 0.40\times 2.0 & = & (0.20 + 0.40)v_{\text{f}}\\0.60 + 0.80 & = & 0.60v_{\text{f}}\\1.40 & = & 0.60v_{\text{f}}\\v_{\text{f}}&=& \dfrac{1.40}{0.60}\\\\& = & \textbf{2.3 m/s}\\\end{array}\\\text{The centre of mass has a velocity of $\large \boxed{\textbf{2.3 m/s}}$}

3 0
3 years ago
What parameters affects the inductance of a coil​
Kazeer [188]

Answer:

Number of Wire Turns in the Coil.

Explanation:

The greater the number of turns of wire in the coil, the greater the inductance. Fewer turns of wire in the coil results in lesser inductance. More coils of wires indicate a greater amount of magnetic field force for a given amount of coil current.

4 0
2 years ago
A block slides on a frictionless, horizontal surface with a speed of 1.32 m/s. The block encounters an unstretched spring and co
Rus_ich [418]

Answer:

Explanation:

The given time is 1 / 4 of the time period

So Time period  of oscillation.

= 4 x .4 =1.6 s

When the block reaches back its original position when it came in contact with the spring for the first time , the block and the spring will have maximum

velocity. After that spring starts unstretching , reducing its speed , so block loses contact as its velocity is not reduced .

So required velocity is the maximum velocity of the block while remaining in contact with the spring.

v ( max ) = w A = 1.32  m /s.

3 0
3 years ago
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