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Alchen [17]
3 years ago
8

NEED HELP ASAP WILL MARK BRAINLIEST

Physics
2 answers:
MissTica3 years ago
8 0

Answer:

A. Atoms of the same element but ith different mass.

Explanation:

Svetradugi [14.3K]3 years ago
4 0

Answer: Isotopes are  Atoms of the same element but with different mass

Explanation: Atoms of the same element but with different mass

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A 1,000 kg car is driving on a 15 m high bridge at 5 m/s. What is the kinetic energy of the car?
yanalaym [24]

Answer:

KE=12,500J

Explanation:

The formula for kinetic energy is:

KE = \frac{1}{2}mv^2

We can plug in the given values into the equation:

KE = \frac{1}{2}*1000kg*(5m/s)^2

KE = 500kg*25m^2/s^2

KE=12,500J

7 0
3 years ago
A small but measurable current of 5.8 × 10-10 A exists in a copper wire whose diameter is 3.0 mm. The number of charge carriers
swat32

Answer:

a) The current density ,J = 2.05×10^-5

b) The drift velocity Vd= 1.51×10^-15

Explanation:

The equation for the current density and drift velocity is given by:

J = i/A = (ne)×Vd

Where i= current

A = Are

Vd = drift velocity

e = charge ,q= 1.602 ×10^-19C

n = volume

Given: i = 5.8×10^-10A

Raduis,r = 3mm= 3.0×10^-3m

n = 8.49×10^28m^3

a) Current density, J =( 5.8×10^-10)/[3.142(3.0×10^-3)^2]

J = (5.8×10^-10) /(2.83×10^-5)

J = 2.05 ×10^-5

b) Drift velocity, Vd = J/ (ne)

Vd = (2.05×10^-5)/ (8.49×10^28)(1.602×10^-19)

Vd = (2.05×10^-5)/(1.36 ×10^10)

Vd = 1.51× 10^-5

8 0
4 years ago
Read 2 more answers
A car comes to a bridge during a storm and finds the bridge washed out. The driver must get to the other side, so he decides to
DerKrebs [107]

Answer:

A) 26.5 m/s

B) 33.0 m/s

Explanation:

A)

  • Once the car leaves the cliff, as no other influence than gravity acts on it, and since it causes the car an acceleration in the vertical direction only, in the horizontal direction, it keeps moving at the same speed until it reaches to the other side.
  • So, we can apply the definition of average velocity to find this speed as follows:

       v_{x} = \frac{\Delta x}{\Delta t}  (1)

  • We know the value of Δx, which is just the wide of the river (53.0m), but we need to find also the value of Δt.
  • This time is given by the vertical movement, whic.h is independent from the horizontal one, because both movements are perpendicular each other.
  • Since the only influence in the vertical direction is due to gravity, the car is accelerated by gravity, with constant acceleration downward equal to g = -9.8m/s² (taking the upward direction as positive).
  • Since the acceleration is constant, we can use the following kinematic equation, as follows:

       \Delta y  = y_{f} - y_{o} = v_{o} * t + \frac{1}{2}  * g *t^{2}  (2)

  • if we take the river level as our x-axis, this means that yf = 1.3 m and

       y₀ = 20.8 m.

  • At the same time, due to in the vertical direction the car has no initial velocity, this means that  v₀ = 0.
  • Replacing by the values in (2) , and solving for t:

       t = \sqrt{\frac{2* \Delta y}{g} } = \sqrt{\frac{2*19.5m}{9.8m/s2} }  = 2 s  (3)

  • If we choose t₀ =0 ⇒ Δt = t = 2 s
  • Replacing Δx and Δt in (1):

       v_{x} = \frac{\Delta x}{\Delta t} = \frac{53.0m}{2s} = 26.5 m/s  (4)

B)

  • When the car is just landing in the other side, the velocity of the car has two components, the horizontal one that we just found in A) and a vertical one.
  • Due to the initial velocity in the vertical direction was just zero, we can find the final velocity just applying the definition of acceleration, with a =g, as follows:

      v_{fy} = g*t = -9.8m/s2*2 s = -19.6 m/s  (5)

  • Since both components are perpendicular each other, we can find the magnitude of the velocity vector (the speed) using the Pythagorean Theorem, as follows:

       v = \sqrt{v_{x}^{2} + v_{fy}^{2} } } = \sqrt{(26.5m/s)^{2} + (-19.6m/s)^{2}}  = 33.0 m/s  (6)

5 0
3 years ago
What are we measuring when you find the temperature of an n substance?
Yuki888 [10]
By measuring the expansion of the substance. In that case you use a thermometer
 
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4 years ago
What will not affect strength of a electromagnet?
Irina18 [472]

The main factors that affect the strength of an electromagnet are: Number of turns on the coil of wire around the core. Strength of the current applied. The material of the coil.

8 0
3 years ago
Read 2 more answers
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