Answer:
730×10 6 g
Explanation:
each one mole of NH4NO3 has 2 moles of nitrogen (2×14)
N NH4NO3
2×14 14+(4×1) +14+(3×16)
28 80
? 2.086 × 10 9
2.086× 10 9 ×28 ÷80 = 730 × 10 6 g of Nitrogen
Answer:
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Explanation:
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1. Diatomic
2. Products
3. Reactants
4. Coefficient
5. Subscript
6. True
7. False
8. First you must write the reactants. Ensure the valencies of the reactants are correct. Draw an arrow. Write the products. Ensure the valencies of the products are correct and apply subscripts as necessary. Balance the equation by ensuring both sides have equal amounts of each elements - use only coefficients to complete this NOT subscripts.
Answer: 78.69 g of Fe
Explanation: Iron(III) oxide is Fe2O3. It has a molar mass of 159.7 g/mole. That consists of:
2 x Fe at 55.85 = 11.69 or 69.94%
3 x O at 16.0 = 48.0 or 30.06%
Therefore 112.5 grams will contain (112.5 g)*(69.94%) = 78.69 g of Fe