Given buffer:
potassium hydrogen tartrate/dipotassium tartrate (KHC4H4O6/K2C4H4O6 )
[KHC4H4O6] = 0.0451 M
[K2C4H4O6] = 0.028 M
Ka1 = 9.2 *10^-4
Ka2 = 4.31*10^-5
Based on Henderson-Hasselbalch equation;
pH = pKa + log [conjugate base]/[acid]
where pka = -logKa
In this case we will use the ka corresponding to the deprotonation of the second proton i.e. ka2
pH = -log Ka2 + log [K2C4H4O6]/[KHC4H4O6]
= -log (4.31*10^-5) + log [0.0451]/[0.028]
pH = 4.15
No, because the appearance has nothing to do with system as well as the fact that appearance is only how it looks
(Btw, that toga picture is like... ughhhh!) hope this helps you ♥︎☀︎☁︎♨︎
Answer:
n don't hv symmetry lines.
so the symmetry of n is 0
Answer:
<em><u>30.11x1</u></em><em><u>0</u></em><em><u>²</u></em><em><u>³</u></em>
Explanation;
brainleist please
Answer:
Hey there!
That would be the alkaline earth metals.
Hope this helps :)
