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3 years ago

12

as a roller coaster car starts down a slope, it’s velocity is 4m/s. But 3 seconds later it’s velocity is 22m/s in the same direc

tion. What is its acceleration

1 answer:

adoni [48]3 years ago

5 0

Formula for acceleration= v2-v1/time
so 22-4/3 is 6m/s^2

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An oceanic depth-sounding vessel surveys the

IgorC [24]

So you would divide 1530 by 8 and that’s how you’d get your answer, so it should be (blank)m

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4 years ago

Flapping flight is very energy intensive. A wind tunnel test

steposvetlana [31]

Answer:

The metabolic power for starting flight=134.8W/kg

Explanation:

We are given that

Mass of starling, m=89 g=89/1000=0.089 kg

1 kg=1000 g

Power, P=12 W

Speed, v=11 m/s

We have to find the metabolic power for starting flight.

We know that

Metabolic power for starting flight= $\frac{P}{m}$

Using the formula

Metabolic power for starting flight= $\frac{12}{0.089}$

Metabolic power for starting flight=134.8W/kg

Hence, the metabolic power for starting flight=134.8W/kg

4 0

4 years ago

The velocity of the wave involved in the Doppler effect:

Margarita [4]

The Doppler Effect provides the equation for the calculation of apparent frequency:

f=fo[vo/(vo-vr)]

where:<span>
vo=source wave velocity
vr=relative speed between source and observer
f=apparent frequency
fo=source frequency </span>

<span>
The velocity of the doppler wave is
v=λf</span>

where λ is light wavelength. Hence,

v=λfo[vo/(vo-vr)]

Based on the equation, we can say that wave velocity will always be defined by one and only one wavelength.

Therefore the answer is letter C.

<span> </span>

4 0

4 years ago

Read 2 more answers

If the v – t graph of a particle is parallel to the t – axis the body has (a) uniform velocity (b) uniform acceleration (c) zero

maxonik [38]

Answer:

zero velocity

Explanation:

if the v-t graph is parallel to the time axis its mean body has covered no path in other words the body is at rest so the velocity of the body should be zero

hope my answer will helps u plz mark me brainlist

5 0

3 years ago

A 22 µF capacitor charged to 0.7 kV and a second 115 µF capacitor charged to 5.5 kV are connected to each other, with the positi

vesna_86 [32]

Answer:

0.099C

Explanation:

First, we need to get the common potential voltage using the formula

$V=\frac {C_2V_2-C_1V_1}{C_1+C_2}$

Where V is the common voltage, C and V represent capacitance and charge respectively. Subscripts 1 and 2 to represent the the first and second respectively. Substituting the above with the following given values then

$C_1=22\times 10^{-6} F\\ C_2=115\times 10^{-6} F\\ V_1= 0.7\times 10^{3}\\V_2=5.5\times 10^{3}$

Therefore

$V=\frac {115\times 10^{-6}\times 5.5\times 10^{3}-22\times 10^{6}\times 0.7\times 10^{3}}{22\times 10^{-6}+115\times 10^{-6}}=4504.3795620437$

Charge, Q is given by CV hence for the first capacitor charge will be $Q_1=C_1V$

Here, $Q_1=22\times 10^{-6}\times 4504.3795620437=0.0990963503649C\approx 0.099C$

8 0

4 years ago