Answer:
Alkene A is more stable than alkene B
Explanation:
Complete question:
The same alkane is obtained from the catalytic hydrogenation of both alkene A and alkene B. The heat of hydrogenation of alkene A is 29.8 kcal/mol, and the heat of hydrogenation of alkene B is 31.4 kcal/mol. Which alkene is more stable ?
Step 1: Data given
The heat of hydrogenation of alkene A is 29.8 kcal/mol
The heat of hydrogenation of alkene B is 31.4 kcal/mol
Step 2: Which alkene is more stable
The smaller the heat of hydrogenation, the more stable the alkene. This because it releases less heat, and has less energy.
29.8 < 31.4
This means alkene A has a smaller heat of hydrogenation than alkene B
Alkene A is more stable than alkene B
The easiest way to approximate ph level is through the ph paper measurement system because using pH paper would be best for doing a quick measurement in the field. It does not essentially need to be calibrated or standardized and the papers make available an instant estimate.
Answer:
To avoid variation due to concentration
Explanation:
Hope this helps :)
They might change because of the flies color
Isobaric transition, first law: <span>H=ΔU+w</span>
for a gas expansion: <span>w=<span>P<span>ext</span></span>∗ΔV</span>
to convert to joules, you need the gas constants.
R = 0.08206 L atm/mol*K, R=8.314 J/mol*K
<span>w=<span>P<span>ext</span></span>∗ΔV∗<span><span>8.314 J/mol∗K</span><span>0.08206 L atm/mol∗K</span></span></span>
<span>ΔU=ΔH−[<span>P<span>ext</span></span>∗ΔV∗<span><span>8.314 J/mol∗K</span><span>0.08206 L atm/mol∗K</span></span>]</span>
<span>ΔU=−75000 J−[(43.0atm)∗(2−5)L∗<span><span>8.314 J</span><span>0.08206 L atm</span></span>]</span>
Then you need to convert to kJ.
by the way U=E, internal energy.