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allsm [11]
3 years ago
12

Which statement about protons is true?

Physics
2 answers:
DENIUS [597]3 years ago
8 0
Answer to your question is A. Because you cannot have HALF of a Proton... 
So of course you will always have a whole number...
White raven [17]3 years ago
4 0
GIVE vo0Mac0ov Brainliest ... He's smart
You might be interested in
Which natural hazards are most likely to affect Florida, due to its geography? Check all that apply. PLS HELP! I WILL GIVE BEST
zhenek [66]

Answer:

drought, floods, rip currents, tropical cyclones, wildfires

Explanation:

right on edge

6 0
3 years ago
A man pushes a stalled car with a force of 100 N. If the acceleration of the car is 0.75 m/s 2 , what is the mass of the car?
shutvik [7]
125 because f=ma so you would use 100=mx0.75
4 0
2 years ago
How fast is a 90kg man running if his kinetic energy is 720 J?
zheka24 [161]
Answer:
4 m/s
Explanation:
KE=1/2mv^2
720=1/2(90)
720=45v^2
divide by 45
16= v^2
over the square root
4=v
v= 4m/s
6 0
3 years ago
People hoping to travel to other worlds are faced with huge challenges. One of the biggest is the time required for a journey. T
Dafna11 [192]

Answer:

The travel would take 6.7 years.

Explanation:

The equation for an object moving in a straight line with acceleration is:

x = x0 + v0 t + 1/2a*t²

where:

x = position at time t

x0 = initial position

v0 = initial velocity

a = acceleration

t = time

In a movement with constant speed, a = 0 and the equation for the position will be:

x = x0 + v t

where v = velocity

Let´s calculate the position from the Earth after half a year moving with an acceleration of 1.3 g = 1.3 * 9.8 m/s² = 12.74  m/s²:

Seconds in half a year:

1/2 year = 1.58 x 10⁷ s

x = 0 m + 0 m/s + 1/2 * 12.74 m/s² * (1.58 x 10⁷ s)²  = 1.59 x 10¹⁵ m

Now let´s see how much time it takes the travel to the nearest star after this half year.

The velocity will be the final velocity achived after the half-year travel with an acceleration of 12.74 m/s²

v = v0 + a t

Since the spacecraft starts from rest, v0 = 0

v = 12.74 m/s² * 1.58 x 10⁷ s = 2.01 x 10 ⁸ m/s

Using the equation for position:

x = x0 + v t

4.1 x 10¹⁶ m = 1.59 x 10¹⁵ m + 2.01 x 10 ⁸ m/s * t

(4.1 x 10¹⁶ m - 1.59 x 10¹⁵ m) / 2.01 x 10 ⁸ m/s = t

t = 2.0 x 10⁸ s * 1 year / 3.2 x 10 ⁷ s = 6.2 years.

The travel to the nearest star would take 6.2 years + 0.5 years = 6.7 years.

7 0
3 years ago
PLEASE HELPPP IF YOU CAN!
Lunna [17]

Answer:

2 m/s²

Explanation:

F = ma

4 = 2(a)

a = 2

3 0
3 years ago
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