2. A wire 4.00 m long and 6.00 mm in diameter has a resistance of 15.0 mΩ. A potential difference of 23.0 V is applied between t
he end. a) What is the current in the wire? b) Calculate the resistivity of the wire material. c) Try to identify the material.
1 answer:
Answer:
Explanation:
a )
current in the wire = potential diff / resistance
= 23 / (15 x 10⁻³ )
= 1.533 x 10³ A .
b )
For resistance of a wire , the formula is
R = ρ L / S where ρ is specific resistance , L is length and S is cross sectional area of wire
putting the given values
15 x 10⁻³ = 4ρ / π x .003²
ρ = 106 x 10⁻⁹ ohm. m
= 10.6 x 10⁻⁸ ohm m
The metal wire appears to be platinum .
You might be interested in
<span>This would be the correct the answer to the following question above.:
Δy=−10=−<span><span>g<span>t22</span></span></span></span>
She say give tow points and write the equation of the line with the two give points (1,5) and (-3,-5 )
Answer:
Is a)
Explanation: i took the test so dw
Answer:
question 1: force
question 2: velocity or inertia
question 3: 0
F = ma
100 N= m . 5 ms⁻¹
100 / 5 = m
20 N ms = mass of object.
