Question

A 0.40-kg mass attached to the end of a string swings in a vertical circle having a radius of 1.8 m. At an instant when the string makes an angle of 40 degrees below the horizontal, the speed of the mass is 5.0 m/s. What is the magnitude of the tension in the string at this instant

Answer 1

Answer:

$T=8.1N$

Explanation:

From the question we are told that:

Mass m=0.40

Radius r=1.8m

Angle Beneath the Horizontal \theta =40 \textdegree

Speed v=5.0m/s

The Tension Angle

 $\alpha=90-\theta\\\\\alpha=90-40$

 $\alpha=50 \textdegree$

Generally the equation for Tension is is mathematically given by

 $T=\frac{mv^2}{r}+mgcos \alpha$

 $T=\frac{0.40*5^2}{1.8}+0.40*5cos50$

 $T=8.1N$