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Anestetic [448]
3 years ago
12

A 0.40-kg mass attached to the end of a string swings in a vertical circle having a radius of 1.8 m. At an instant when the stri

ng makes an angle of 40 degrees below the horizontal, the speed of the mass is 5.0 m/s. What is the magnitude of the tension in the string at this instant
Physics
1 answer:
enyata [817]3 years ago
7 0

Answer:

T=8.1N

Explanation:

From the question we are told that:

Mass m=0.40

Radius r=1.8m

Angle Beneath the Horizontal \theta =40 \textdegree

Speed v=5.0m/s

The Tension Angle

 \alpha=90-\theta\\\\\alpha=90-40

 \alpha=50 \textdegree

Generally the equation for Tension is is mathematically given by

 T=\frac{mv^2}{r}+mgcos \alpha

 T=\frac{0.40*5^2}{1.8}+0.40*5cos50

 T=8.1N

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The forces on the  y axis are:

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The forces in the x axis are:

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A material kept at high temperature is seen to emit photons with energies of 0.3 eV, 0.5 eV, 0.8 eV, 2.0 eV, 2.5 eV, and 2.8 eV.
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Answer:

0.3 eV, 0.5eV,, 8 eV, 2.0eV, 2.50 eV, 2.8 eV

Explanation:

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In the absorption process, the material is at low temperature, ideally at A = 0K, whereby all states are in the ground state and all excited states are empty. therefore it can absorb the beam energy for each transition given from the ground state to each excited edtado.

Consequently, the lines above the absorption oscillate lines coincide with the lines of emotion, this we see lines oscillate at 0.3 eV, 0.5eV,, 8 eV, 2.0eV, 2.50 eV, 2.8 eV

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Answer:

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Explanation:

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Computation:

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Number of photons emit per second = 1897.689 × 10²⁶

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