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2 years ago

Why use units with your number? Why is putting a unit with your number important?

2 answers:

5 0

Assume you need to know to what extent it will take you to get from your
house to some other place. You ask me, and I say, "It will take 5."
5 what? 5 minutes? 5 hours? 5 days?
We utilize numbers to speak to stuff on the planet. Some of the time it's simply
checking, e.g.,
I discovered 9 mushrooms today.
I discovered 18 yesterday.
So now I have 9 + 18 = 27 mushrooms.
Yet, some of the time we're utilizing numbers to speak to things that we measure,
like separations or weights or ranges:
I have a board 12 feet long.
I need to cut it into pieces 3 feet long.
I can cut it into (12 feet)/(3 feet for each piece) = 4 pieces.
We can utilize diverse methods for measuring something, e.g.,
I have a board 144 inches in length.
I need to cut it into pieces 3 feet long.
In the event that I simply isolate 144 by 3, without focusing on units, I get an
reply of 48. In any case, what does it mean? It's an indistinguishable issue from
some time recently, since 144 inches is an indistinguishable thing from 12 feet! So I would do well to
find a similar solution - 4 pieces, not 48. To find a similar solution, I have
to change my units:
I have a board 144 inches in length.
I need to cut it into pieces 36 inches long.
I can cut it into (144 inches)/(36 inches per piece) = 4 pieces.
So units are the means by which we ensure that our figurings about the world

jek_recluse [69]2 years ago

3 0

Answer:

Explanation:

When we measure a given physical quantity then after measurement we give the magnitude as well as unit along with the measurement

Here number gives the magnitude of the measurement what we did and unit gives an idea what unit is for the given measurement we used

Here unit is essential while we did any measurement because unit of the measurement may be different for different group of people but the quantity is always same when we compare them along with the unit

For example we know that

$1 ft = 12 inch$

here the numbers are different in two unit system but the quantity we compared is same.

so it is always essential to put units with all measurement to have complete idea of the quantity that is measured

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A person who weighs 150 pounds on Earth would weigh ____ pounds on the moon.

enot [183]

Answer:

25lb

Explanation:

You haven't changed (you are made up of the same atoms), but the force exerted on you is different. Physicists like to say that your mass hasn't changed, only your weight.

6 0

3 years ago

Physics question i appreciate your help please

den301095 [7]

Solution: From the given question, we shall find the vector quantity among the

(A) Time , (B) Velocity, (C) Distance , (D) Speed

Concept: <u>Vector Quantity: </u>All those physical quantities which have magnitude as well as specific directions, are called Vector Quantities.

Here, Time, Distance and Speed have only magnitude but have no directions so they will be scalar quantities.

Now, <u>Velocity:</u> It is defined as the change in displacement per unit time. Since the change in the displacement will be in particular direction only. Hence, velocity will be the vector quantity.

Hence, the option (B) Velocity will be the correct option.

4 0

3 years ago

Compared to the cells in a healthy body, Elisa’s cells are getting far fewer ____________________ molecules.

Elenna [48]

Answer:

glucose

Explanation:

7 0

3 years ago

Each plate of a parallel‑plate capacitor is a square of side 4.19 cm, 4.19 cm, and the plates are separated by 0.407 mm. 0.407 m

alexandr1967 [171]

Answer:

The electric field strength inside the capacitor is 49880.77 N/C.

Explanation:

Given:

Side length of the capacitor plate (a) = 4.19 cm = 0.0419 m

Separation between the plates (d) = 0.407 mm = $0.407\times 10^{-3}\ m$

Energy stored in the capacitor (U) = $7.87\ nJ=7.87\times 10^{-9}\ J$

Assuming the medium to be air.

So, permittivity of space (ε) = $8.854\times 10^{-12}\ F/m$

Area of the square plates is given as:

$A=a^2=(0.0419\ m)^2=1.75561\times 10^{-3}\ m^2$

Capacitance of the capacitor is given as:

$C=\dfrac{\epsilon A}{d}\\\\C=\frac{8.854\times 10^{-12}\ F/m\times 1.75561\times 10^{-3}\ m^2 }{0.407\times 10^{-3}\ m}\\\\C=3.819\times 10^{-11}\ F$

Now, we know that, the energy stored in a parallel plate capacitor is given as:

$U=\frac{CE^2d^2}{2}$

Rewriting in terms of 'E', we get:

$E=\sqrt{\frac{2U}{Cd^2}}$

Now, plug in the given values and solve for 'E'. This gives,

$E=\sqrt{\frac{2\times 7.87\times 10^{-9}\ J}{3.819\times 10^{-11}\ F\times (0.407\times 10^{-3})^2\ m^2}}\\\\E=49880.77\ N/C$

Therefore, the electric field strength inside the capacitor is 49880.77 N/C

8 0

3 years ago

A race car has a centripetal acceleration of 15.625 m/s2 as it goes around a curve. If the curve is a circle with radius 40 m, w

myrzilka [38]

The centripetal acceleration is given by
$a_c = \frac{v^2}{r}$
where v is the tangential speed and r the radius of the circular orbit.

For the car in this problem, $a_c = 15.625 m/s^2$ and r=40 m, so we can re-arrange the previous equation to find the velocity of the car:
$v= \sqrt{a_c r}= \sqrt{(15.625 m/s^2)(40 m)}=25 m/s$

8 0

2 years ago