Answer:
(a) The charge on capacitor in first case is C
(b) In second case is C
(c) Potential across plate is 24 V
(d) Work required to pull the plates is J
Explanation:
Given:
Area of plate
Voltage V
Separation between two plate m
(a)
The charge on capacitor is given by,
But capacitance of parallel plate capacitor is given by,
⇒
Where
C
(b)
The charge on the capacitor when plate separation is m is,
Here m
C
(c)
The potential difference across plate is,
But
F
Put the value of capacitance and find potential difference,
V
(d)
Work required is given by,
Where V and
J
Therefore, the charge on capacitor in first case is C and in second case is C and potential across plate is 24 V and work required to pull the plates is J