Answer:
Wavelength of light in diamond λ2 = 179.75 nm (Approx.)
Explanation:
Given:
Blue light of wavelength λ1 = 435 nm
n2 in diamond = 2.42
Find:
Wavelength of light in diamond λ2
Computation:
Since the wavelength is smaller, the frequency stays constant. The frequency of vibrations does not shift when they pass from one source to the next.
So,
n1λ1 = n2λ2
(1)(435) = (2.42)λ2
Wavelength of light in diamond λ2 = 179.75 nm (Approx.)
Answer:
d
Explanation:
Ya gon find the Kenitic Energy first
K=½mv²===> K=½×0.2×(0.2)²===> 0.1(0.04)===> 0.004
and now the replacement:
0.004=½×0.4V²====> v²=0.02===> V=0.14m/s
Base in your questions that ask what cause the bright lines seen in the emission spectrum and i think the best answer to that is the H2 gas is used when protons was heated so the electron absorb all the photons and get exited and resulted by given of a light.