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AysviL [449]
4 years ago
9

Hi! Plz help? Which term identifies the effects of the buildup of stationary electric charges on everyday objects caused by the

transfer of electrons from one object to another? A. stationary electricity B. current electricity C. magnetic electricity D. static electricity
Physics
1 answer:
erma4kov [3.2K]4 years ago
8 0
<span>The question is, which term identifies the effects of build up of stationary electric charges on every day objects caused by the transfer of electrons from one object to another. The correct option is D. Static energy is defined as an imbalance of positive and negative charges within or on the surface of an object. The charge usually remain on the object until it is moved away by discharge. </span>
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A car starts from rest and accelerates with a constant acceleration of 1.00 m/s2 for 3.00 s. The car continues for 5.00 s at con
barxatty [35]

Answer:

19.5 m

Explanation:

Using the equation of motion,

For the first 3 seconds,

s = ut +1/2at².......................... Equation 1

Where t = time, u = initial velocity, a = acceleration, s = distance

Note: Since the car starts from rest, u = 0 m/s.

Given: a = 1.0 m/s, t = 3 s, u = 0 m/s

Substitute into equation 1

s = 0×3+1/2(3)²(1)

s = 9/2

s = 4.5

In the remaining five seconds, at a constant velocity,

s' = vt............. Equation 2

Where v = velocity, t = time.

Recall,

v = u+at

v = 0+1(3)

v = 3 m/s.

Also, t = 5 s.

Substitute into equation 2

s' = 3(5)

s' = 15 m.

Total distance = 15+4.5

Total distance = 19.5 m.

Hence the car travels 19.5 m

8 0
3 years ago
Human blood has a density of approximately 1.05×10'3 kg/m'3 .Use this to estimate the difference in blood pressure between the b
Murljashka [212]

Answer:

formula

ΔP= PgΔh

Explanation:

Calculation.

ΔP = (1.05 x 10^3kg/m^3)(9.8m/s^2)(6ft equivalent to 1.8288m)

ΔP = 1.05 x 10^3 kg/m^3 x 9.8m/s^2.

x1.8288.

ΔP = 1.88 x 10^4 Pa.

8 0
3 years ago
The position of a particle moving along the x axis varies in time according to the expression x = 4t 2, where x is in meters and
Pie

Answer:

a) X = 17.64 m

b) X = 17.64 + 4∆t^2 + 16.8∆t

c) Velocity = lim(∆t→0)⁡〖∆X/∆t〗 = 16.8 m/s

Explanation:

a) The position at t = 2.10s is:  

                 X = 4t^2

                 X = 4(2.10)^2

                 X = 17.64 m

b) The position at t = 2.10 + ∆t s  will be:

                 X = 4(2.10 + ∆t)^2

                 X = 17.64 + 4∆t^2 + 16.8∆t  m

c) ∆X is the difference between position at t = 2.10s and t = 2.10 + ∆t so,

                 ∆X= 4∆t^2 + 16.8∆t

Divide by ∆t on both sides:  

                ∆X/∆t =  4∆t + 16.8

 Taking the limit as ∆t approaches to zero we get:  

              Velocity =lim(∆t→0)⁡〖∆X/∆t〗 = 4(0) + 16.8

              Velocity = 16.8 m/s

 

8 0
3 years ago
Read 2 more answers
A block of mass 0.221 kg is placed on top of a light, vertical spring of force constant 5365 N/m and pushed downward so that the
Anvisha [2.4K]

Answer:

The maximum height above the point of release is 11.653 m.

Explanation:

Given that,

Mass of block = 0.221 kg

Spring constant k = 5365 N/m

Distance x = 0.097 m

We need to calculate the height

Using stored energy in spring

U=\dfrac{1}{2}kx^2...(I)

Using gravitational potential energy

U' =mgh....(II)

Using energy of conservation

E_{i}=E_{f}

U_{i}+U'_{i}=U_{f}+U'_{f}

\dfrac{1}{2}kx^2+0=0+mgh

h=\dfrac{kx^2}{2mg}

Where, k = spring constant

m = mass of the block

x = distance

g = acceleration due to gravity

Put the value in the equation

h=\dfrac{5365\times(0.097)^2}{2\times0.221\times9.8}

h=11.653\ m

Hence, The maximum height above the point of release is 11.653 m.

3 0
3 years ago
A hand-held video game is powered by batteries. After playing the game for several minutes, a student notices that the game feel
scoundrel [369]
I would say your answer is B- Some of the chemical energy from the batteries is converted into heat energy. 
7 0
4 years ago
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