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IrinaVladis [17]
4 years ago
5

Put the substance in a 25 mL beaker.

Chemistry
2 answers:
kkurt [141]4 years ago
5 0

Answer: 1. Liquid

2. oily

3. no (not a solid)

Explanation:

Alexandra [31]4 years ago
4 0

Answer:

State of matter: Liquid

Appearance and texture: Oily

Crystalline structure: No not a solid

Explanation:

did the quiz and got it right

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How much does 200 gallons of water weigh?
Jlenok [28]
To be able to obtain the mass of the given volume of a substance, we need data on its density since it is the mass per volume of a substance. We multiply this value to the given volume. For water, it is approximately <span>10.02 lb/gal.

Mass of water = 200 gal ( 10.02 lb/gal ) = 200.4 lb

Hope this helped.</span>
3 0
3 years ago
How does a catalyst increase the rate of a reaction?
Norma-Jean [14]

Answer:

C) It provides a lower activation energy for the reaction is the correct answer.

Explanation:

  • A catalyst increases the rate of the chemical reaction by lowering the activation energy for a reaction.
  • Catalyst is used to increase the reaction rate, it remains unchanged in the chemical reaction and it does not change the equilibrium constant.
  • Activation energy is a minimum amount of energy required to initiate the reaction.

6 0
3 years ago
Does the moon make its own light? Explain.
-Dominant- [34]

Answer:

No moon has no light.

Explanation:

It only reflects the light coming from the sun. Only star produces light and moon is a satellite that revolvs around the earth.

5 0
3 years ago
Read 2 more answers
Please let me know if this is correct?
siniylev [52]

Answer: Yes! you're all good. Alkali metals in group 1 are the most metallic :)

6 0
3 years ago
A sample compound contains 5.723g Ag, 0.852g S and 1.695g O. Determine its empirical formula.
Lubov Fominskaja [6]

Answer:

Ag_2SO_4

Explanation:

Formula for the calculation of no. of Mol is as follows:

mol=\frac{mass\ (g)}{molecular\ mass}

Molecular mass of Ag = 107.87 g/mol

Amount of Ag = 5.723 g

mol\ of\ Ag=\frac{5.723\ g}{107.87\ g/mol} =0.05305\ mol

Molecular mass of S = 32 g/mol

Amount of S = 0.852 g

mol\ of\ S=\frac{0.852\ g}{32\ g/mol} =0.02657\ mol

Molecular mass of O = 16 g/mol

Amount of O = 1.695 g

mol\ of\ O=\frac{1.695\ g}{16\ g/mol} =0.10594\ mol

In order to get integer value, divide mol by smallest no.

Therefore, divide by 0.02657

Ag, \frac{0.05305}{0.02657} \approx 2

S, \frac{0.02657}{0.02657} \approx 1

O, \frac{0.10594}{0.02657} \approx 4

Therefore, empirical formula of the compound = Ag_2SO_4

7 0
4 years ago
Read 2 more answers
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