Here is the correct question
You mix 125 mL of 0.170 M CsOH with 50.0 mL of 0.425 M HF in a coffee-cup calorimeter, and the temperature of both solutions rises from 20.20 °C before mixing to 22.17 °C after the reaction. What is the enthalpy of reaction per mole of ? Assume the densities of the solutions are all 1.00 g/mL, and the specific heat capacities of the solutions are 4.2 J/g · K. Enthalpy of reaction = kJ/mol
Answer:
75.059 kJ/mol
Explanation:
The formula for calculating density is:

Making mass the subject of the formula; we have :
mass = density × volume
which can be rewritten as:
mass of the solution = density × volume of the solution
= 1.00 g/mL × (125+ 50 ) mL
= 175 g
Specific heat capacity = 4.2 J/g.K
∴ the energy absorbed is = mcΔT
= 175 × 4.2 × (22.17 - 20.00) ° C
= 1594.95 J
= 1.595 J
number of moles of CsOH = 
= 0.2125 mole
Therefore; the enthalpy of the reaction = 
= 
= 75.059 kJ/mol
38K
-391°F
Explanation:
Given temperature:
Temperature of Triton = -235°C
Unknown:
Surface temperature of Triton in °F and Kelvin
Solution:
Temperature is the degree of hotness or coldness of a body.
It is usually measured using units of kelvin, degree Celsius and degree Fahrenheit.
tK = 273 + t°C from °C to K
t°F =
t°C + 32
tk = temperature in kelvin
t°C = temperature in Celsius
t°F = temperature in Fahrenheit
tK = 273 + (-235) = 38K
t°F =
x (-235) + 32 = -423 + 32 = -391°F
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Suspension. The particles are big enough for the eye to see, and will separate if left sitting.
Answer:
it's A
Explanation:
product being used by everyone
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Answer:
16 mol O2
Explanation:
CO + 2 O2 -> 2 CO2
1 mol CO -> 2 mol O2
8 mol CO -> x
x= (8 mol CO * 2 mol O2)/1 mol CO
x= 16 mol O2