A wave will "break" because the bottom interferes with its oscillatory motion. Breaking of waves may occur anywhere that the amplitude is sufficient, including in mid-ocean. When waves enter shallow water they break because the motion of water in lower part of the wave nearest the bottom is slowed by friction so that their oscillation is faster than its supporting portion at the bottom. Thus, the wave collapses forward and breaks.
In series connection in orde to find the total resistance we add all the resistance capacity but in parallel, we take the 1/R and resistance = V hence the series connection takes up more power,
Answer:
is constant
Explanation:
Energy cannot be destroyed or created, but can transfer from places to places and in different forms.
Answer:
Hoop will reach the maximum height
Explanation:
let the mass and radius of solid ball, solid disk and hoop be m and r (all have same radius and mass)
They all are rolled with similar initial speed v
by the law of conservation of energy we can write
for solid ball
![[tex]\frac{1}{2}mv^2+\frac{1}{2}I_{ball}\omega^2= mgh_{ball}](https://tex.z-dn.net/?f=%5Btex%5D%5Cfrac%7B1%7D%7B2%7Dmv%5E2%2B%5Cfrac%7B1%7D%7B2%7DI_%7Bball%7D%5Comega%5E2%3D%20mgh_%7Bball%7D)
putting 
in the above equation and solving we get
now for solid disk
![[tex]\frac{1}{2}mv^2+\frac{1}{2}I_{disk}\omega^2= mgh_{disk}](https://tex.z-dn.net/?f=%5Btex%5D%5Cfrac%7B1%7D%7B2%7Dmv%5E2%2B%5Cfrac%7B1%7D%7B2%7DI_%7Bdisk%7D%5Comega%5E2%3D%20mgh_%7Bdisk%7D)
putting 
in the above equation and solving we get
for hoop
![[tex]\frac{1}{2}mv^2+\frac{1}{2}I_{hoop}\omega^2= mgh_{hoop}](https://tex.z-dn.net/?f=%5Btex%5D%5Cfrac%7B1%7D%7B2%7Dmv%5E2%2B%5Cfrac%7B1%7D%7B2%7DI_%7Bhoop%7D%5Comega%5E2%3D%20mgh_%7Bhoop%7D)
putting 
in the above equation and solving we get
clearly from the above calculation we can say that the Hoop will reach the maximum height
When viewing an object through a convex lens, the object appears smaller. Thus, B. things look smaller than they actually are. The way that light bends as it passes through a convex lens results in these shrunken images; moreover, the image of a convex lens is also upside down.
