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WINSTONCH [101]
3 years ago
7

For an increase in the bulk modulus of a material but without any change in the density, what happens to the speed of sound in t

hat material?
Physics
1 answer:
vazorg [7]3 years ago
7 0
The speed of sound, c, is given by the Newton-Laplace formula
c = \sqrt{ \frac{K}{\rho} }
where
K = bulk modulus
ρ =  density

Because the density is constant, the speed of sound is proportional to the square root of the bulk modulus.

Therefore when the bulk modulus increases, the speed of sound increases by the square root of the bulk modulus.

For example, if K is doubled, then
c = \sqrt{2K} = \sqrt{2} \sqrt{K}

Answer:
If the bulk modulus increases by a factor of n, then c increases by a factor of √n.

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According to kinetic theory, which two factors are important for a successful reaction to occur?
fgiga [73]

Answer:

Molecules must collide with sufficient energy, known as the activation energy, so that chemical bonds can break. Molecules must collide with the proper orientation.

Explanation:

A collision that meets these two criteria, and that results in a chemical reaction, is known as a successful collision or an effective collision.

6 0
2 years ago
A 81 kg man is riding on a 40 kg cart traveling at a speed of 2.3 m/s. He jumps off with zero horizontal speed relative to the g
Alexus [3.1K]

Answer:

\Delta v= 4.66\frac{m}{s}

Explanation:

In this case we have to use the Principle of conservation of Momentum:

<em>This principle says that in a system  the total momentum is constant if no external forces act in the system. The formula is:</em>

m_1v_1+m_2v_2=m_1u_1+m_2u_2

<em>Where:</em>

m_1: Mass of the first object.

m_2: Mass of the second object.

v_1: Initial velocity of the first object.

v_2: Initial velocity of the second object.

u_1: Final velocity of the first object.

u_2: Final velocity of the second object.

In <u>this problem</u> we have:

m_1=81kg\\m_2=40kg\\v_1_2=2.3\frac{m}{s}

u_1=0\frac{m}{s}

Observation: v_1_2: Is because the system has the same initial velocity.

First we have to find u_2,

m_1v_1+m_2v_2=m_1u_1+m_2u_2

We can rewrite it as:

(m_1+m_2)v_1_2=m_1u_1+m_2u_2

Replacing with the data:

(m_1+m_2)v_1_2=m_1u_1+m_2u_2\\\\(81kg+40kg)2.3\frac{m}{s}=81kg(0\frac{m}{s})+40kg(u_2)\\\\(121kg)2.3\frac{m}{s}=40kg(u_2)\\\\\frac{(121kg)2.3\frac{m}{s}}{40kg}=u_2\\\\\frac{278.3}{40}\frac{m}{s}=u_2\\\\6.96\frac{m}{s}=u_2

We found the final velocity of the cart, but the problem asks for the resulting change in the cart speed, this means:

\Delta v=u_2-v_2\\\Delta v=6.96\frac{m}{s}-2.3\frac{m}{s}\\\Delta v= 4.66\frac{m}{s}

Then, the resulting change in the cart speed is:

\Delta v= 4.66\frac{m}{s}

5 0
3 years ago
Safety warning: What three problems can happen when you connect a short wire between the positive and negative ends of a battery
STALIN [3.7K]

Answer:

if you're not safe then 1 cause is you can get very hurt and also you could be in very deep Danger and the last reason is you could also get killed

4 0
3 years ago
Ignoring friction, what is the acceleration of a 75.0 kg object which is acted upon by an
natulia [17]

Explanation:

we can use the formula F = ma

hence,

500 = 75a

a = 6.666 m/s² or 6(2/3) m/s²

hope this helps.

3 0
2 years ago
hhhhhhhhhhhhheeeeeeeeeeeeeellllllllllpppppppppppp ppppppplllllllllzzzzzzzz hhhhhhhheeeeeeeellllllllppppppp !!!!!!!!!!!!!!!!!! :)
Setler79 [48]

Answer: Sorry the pic is too blurry try making the resolution higher

6 0
3 years ago
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