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iragen [17]
3 years ago
6

A) What magnitude point charge creates a 12596.37 N/C electric held at a distance of 0.593 m?

Physics
1 answer:
Oksana_A [137]3 years ago
8 0

Answer:

Q = 4.9216 * 10^{-7}C

Explanation:

Given

E = 12596.37 N/C

r = 0.593m

Required

Determine the magnitude point charge (Q)

This question will be solved using the\ magnitude of the electric field formula

E = \frac{kQ}{r^2}<em> </em>

Where

k = 9 * 10^9\ Nm^2 / C^2

Make Q the subject in E = \frac{kQ}{r^2}

E * r^2 = kQ

Q = \frac{E * r^2}{k}

Substitute values for E, r and k

Q = \frac{12596.37 * 0.593^2}{9 * 10^9}

Q = \frac{4429.50}{9 * 10^9}

Q = \frac{492.16}{10^9}

Q = 492.16 * 10^{-9}

Express in standard form

Q = 4.9216 * 10^2 * 10^{-9}

Q = 4.9216 * 10^{2-9}

Q = 4.9216 * 10^{-7}C

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She threw the marshmallow at a speed of around 4.76 m/s.The formula for the horizontal range gives the velocity.

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The motion of an item hurled or projected into the air, subject only to gravity's acceleration, is known as projectile motion.

The item is known as a projectile, and the course it takes is known as a trajectory. Falling object motion is a simple one-dimensional kind of projectile motion with no horizontal movement.

Given data;

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Range,R =  3 m

Initial velocity,u

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The projectile's motion is divided into two parts: horizontal and vertical motion.

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Hence, she throws the marshmallow at a speed of 4.76 m/sec.

To learn more about the projectile motion refer to the link;

brainly.com/question/11049671

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A runner begins from rest at the starting line and travles for 6.5 seconds, a runner reaches a speed of 13.4 m/s what is the run
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The acceleration of the runner in the given time is 2.06m/s².

Given the data in the question;

Since the runner begins from rest,

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Acceleration of the runner; a = \ ?

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Velocity is the speed at which an object moves in a particular direction.

Acceleration is simply the rate of change of the velocity of a particle or object with respect to time. Now, we can see the relationship from the First Equation of Motion

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Where v is final velocity, u is initial velocity, a is acceleration and t is time elapsed.

To determine the acceleration of the runner, we substitute our given values into the equation above.

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Hello there.

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Final answer:

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