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3 years ago

6

BRAINLIESTTTTTT PLEASEEEEEE

2 answers:

Bingel [31]3 years ago

7 0

The final exams have the smaller IQR

Olenka [21]3 years ago

4 0

To find interquartile range, you have to find quartile 1 and quartile 3. Then, you subtract to two to find interquartile range. To solve this problem, I first found quartile 1 and quartile 3 which are 80 and 92, respectively. Then I subtracted 80 from 92 which got me the interquartile range for the midterm data. Then, to find the interquartile range for the finals data, I did the same thing and I got 78 and 85 which gave me an interquartile range of 7. So, for the answer, I got c. the final exams.

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jeka57 [31]

Answer:

Step-by-step explanation:

8 0

3 years ago

erastovalidia [21]

Answer:

D.) 4x + y

Step-by-step explanation:

3x + x + y

Add 3 x and x .

4 x + y

7 0

3 years ago

Given each pair of similar triangles find the missing value. of LJK=PQR find x

Svetlanka [38]

Answer:

1

Step-by-step explanation:

3 0

3 years ago

P: x – 5 =10 q: 4x + 1 = 61 Which is the inverse of p → q?

Lesechka [4]

The inverse is b. If 4x+1 .NE. 61, then x-5 .NE.10

3 0

3 years ago

Read 2 more answers

Which points lie on the line whose equation is 8x - 2y + 7 = -9? Select all that apply.

Anestetic [448]

Answer:

A.(-2, 0)

C. (-1.4)

Step-by-step explanation:

we know that

If a point lie on the line, then the point must satisfy the equation of the line (makes the equation true)

we have

$8x-2y+7=-9$

subtract 7 both sides

$8x-2y=-9-7$

$8x-2y=-16$

divide by 2 both sides

$4x-y=-8$

Substitute the value of x and the value of y of each point in the linear equation and analyze the result

<u><em>Verify each point</em></u>

case A) we have

(-2, 0)

For x=-2, y=0

substitute

$4(-2)-(0)=-8$

$-8=-8$ ---> is true

so

the point lie on the line

case B) we have

(1, 3)

For x=1, y=3

substitute

$4(1)-(3)=-8$

$1=-8$ ---> is not true

so

the point not lie on the line

case C) we have

(-1, 4)

For x=-1, y=4

substitute

$4(-1)-(4)=-8$

$-8=-8$ ---> is true

so

the point lie on the line

case D) we have

(1, -4)

For x=1, y=-4

substitute

$4(1)-(-4)=-8$

$8=-8$ ---> is not true

so

the point not lie on the line

case E) we have

(0, -1)

For x=0, y=-1

substitute

$4(0)-(-1)=-8$

$1=-8$ ---> is not true

so

the point not lie on the line

7 0

3 years ago