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3 years ago

BRAINLIESTTTTTT PLEASEEEEEE

Mathematics

2 answers:

Bingel [31]3 years ago

7 0

The final exams have the smaller IQR

Olenka [21]3 years ago

4 0

To find interquartile range, you have to find quartile 1 and quartile 3. Then, you subtract to two to find interquartile range. To solve this problem, I first found quartile 1 and quartile 3 which are 80 and 92, respectively. Then I subtracted 80 from 92 which got me the interquartile range for the midterm data. Then, to find the interquartile range for the finals data, I did the same thing and I got 78 and 85 which gave me an interquartile range of 7. So, for the answer, I got c. the final exams.

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How do you write 21% as a decimal

Goshia [24]

Answer:

0.21

Step-by-step explanation:

if you write it as a fraction it would be 21/100

and if that is made to a decimal it would be 0.21 .

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3 years ago

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Multiply (9x + 2) (2x - 3). What is the product?

garik1379 [7]

Answer:

18x^2-23x-6

Step-by-step explanation:

multiply: 9x*2x-9x*3+2*2x-2*3

18x^2-9X(3)3+2(2X)-2(3)

18X^2-27x+4x-6

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3 years ago

In the past, 21% of all homes with a stay-at-home parent, the father is the stay-at-home parent. An independent research firm ha

Afina-wow [57]

Answer:

A sample size of 79 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$\pi = 0.21$

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

What sample size is needed if the research firm's goal is to estimate the current proportion of homes with a stay-at-home parent in which the father is the stay-at-home parent with a margin of error of 0.09?

A sample size of n is needed.

n is found when M = 0.09. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.09 = 1.96\sqrt{\frac{0.21*0.79}{n}}$