a. Length of the fence around the field = perimeter of quarter circle = 892.7 ft.
b. The area of the outfield is about 39,584 sq. ft..
<h3>What is the Perimeter of a Quarter Circle?</h3>
Perimeter of circle = 2πr
Perimeter of a quarter circle = 2r + 1/4(2πr).
a. The length of the fence around the field = perimeter of the quarter circle fence
= 2r + 1/4(2πr).
r = 250 ft
Plug in the value
The length of the fence around the field = 2(250) + 1/4(2 × π × 250)
= 892.7 ft.
b. Size of the outfield = area of the full field (quarter circle) - area of the infield (cicle)
= 1/4(πR²) - πr²
R = radius of the full field = 250 ft
r = radius of the infield = 110/2 = 55 ft
Plug in the values
Size of the outfield = 1/4(π × 250²) - π × 55²
= 49,087 - 9,503
= 39,584 sq. ft.
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For this case we have the following expression:
(xy ^ -6) / (x ^ -4y ^ 2)
By power properties we can rewrite the expression as:
(x * x ^ 4) / (y ^ 6 * y ^ 2)
Then, for power properties:
Same exponents are added:
(x ^ (4 + 1)) / (y ^ (6 + 2))
(x ^ 5) / (y ^ 8)
Answer:
An expression after the negative exponents have been eliminated is:
(x ^ 5) / (y ^ 8)
1 kilometer=1000 meters so the 8 kilometers he ran would be 8000 meters then theres the 500 he sprinted. he climbed bleachers for 1.5 kilometers which would equal 1500 meters so 8000+500+1500=10,000. He traveled 10,000 kilometers.