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Novay_Z [31]
3 years ago
12

Match these terms with their definitions: 1. unit of electrical resistance ampere 2. unit of electromotive force or electrical p

otential ohm 3. unit for measuring the strength of an electric current volt 4. unit of electrical power watt
Physics
2 answers:
Sedaia [141]3 years ago
6 0
Resistance- ohm
current- ampere
power- watt
electromotive force- volt
aksik [14]3 years ago
5 0

Explanation:

Electrical resistance is provided by the resistors. It is defined as the devices that opposes the flow of electric current in the circuit. Its SI unit is ohms.

Electromotive force or electrical potential is defined as the work done by the unit positive charge in moving form one point to another. Its SI unit is volt.

Electric charge per unit time is called electric current. Its SI unit is ampere.

Electric power is defined as the product of potential difference or voltage and current flowing. Its SI unit is watts.

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A 37 kg object has an applied force of 85N [R] acting on it. The coefficient of
Sliva [168]

Answer:

Explanation:

This is quite tricky! You need to do 2 different equations to solve all the parts of this problem. First is finding the acceleration in one dimension, which has an equation of

F - f = ma

where F is the applied Friction,

f is the frictional force acting against F,

m is the mass of the object, and

a is the acceleration of the object (NOT the velocity!)

This is Newton's Second Law expanded on a bit. The sum of the forces working on an object is equal to the object's mass times its acceleration. We have F, but we need f which is found in the equation

f = μF_n which is the coefficient of kinetic friction times the weight of the object. Weight is found in the equation

w = mg where m is mass and g is the pull of gravity. Let's start there and work backwards:

w = 37(9.8) to 2 sig figs so

w = 360N. Now fill that in to find f:

f = (.17)(360) to 2 sig figs so

f = 61. Now for the final answer in the original equation way back up at the top:

85 - 61 = 37a and do the subtraction on the left side first:

24 = 37a and then we divide to 2 sig figs to get

a = .65 m/s/s

Since we are moving in a straight line (as opposed to on an angle) the displacement is found in

d = rt which simply says that the distance an object moves is equal to its rate times the time. Therefore,

d = 2.2(3.4) to 2 sig figs so

d = 7.5 m

6 0
3 years ago
A delivery man starts at the post office, drives 40 km north, then 20 km west, then 60 km northeast, and finally 50 km north to
Vesnalui [34]



assuming north-south along the Y-axis and east-west along the X-axis

X = total X-displacement

from the graph , total displacement along X-direction is given as

X = 0 - 20 + 60 Cos45 + 0

X = 42.42 - 20

X = 22.42 m


Y = total Y- displacement

from the graph , total displacement along Y-direction is given as

Y = 40 + 0  + 60 Sin45 + 50

Y = 90 + 42.42

Y = 132.42 m

magnitude of the net displacement vector using Pythagorean theorem is given as

magnitude : Sqrt(X² + Y²) = Sqrt(22.42² + 132.42²) = 134.31 m

Direction : tan⁻¹(Y/X) = tan⁻¹(132.42/22.42) = 80.4 deg north of east


4 0
3 years ago
Dos masas de 8kg es tan unidas en el extremo de una varilla de aluminio de 400mm de longitud. La varilla está sostenida en su pa
enyata [817]

Answer:

The maximum frequency of revolution is 3.6 Hz.

Explanation:

Given that,

Mass = 8 kg

Distance = 400 mm

Tension = 800 N

We need to calculate the velocity

Using centripetal force

F=\dfrac{mv^2}{r}

Where, F= tension

m = mass

v= velocity

r = radius of circle

Put the value into the formula

800=\dfrac{8\times v^2}{200\times10^{-3}}

v^2=\sqrt{\dfrac{800\times200\times10^{-3}}{8}}

v=4.47\ m/s

We need to calculate the maximum frequency of revolution

Using formula of frequency

f=\dfrac{v}{2\pi r}

Put the value into the formula

f=\dfrac{4.47}{2\pi\times200\times10^{-3}}

f=3.6\ Hz

Hence, The maximum frequency of revolution is 3.6 Hz.

7 0
3 years ago
What voltage (potential difference)must be applied to a 26 1
12345 [234]

Answer:

26v

....................

3 0
3 years ago
Are there any difference betwn supersonic planes and concorde planes​
malfutka [58]

<u>Answer</u>:

Yes, there are differences between supersonic planes and concorde planes​

<u>Explanation</u>:

The supersonic planes moves faster than the speed of sound. But these flights are banned because it is economically non-starter.  It has more loud sound equivalent to the explosion. The banned was elevated in 2003, due to new aviation law. The concords travel twice the speed of sound. This planes holds the record for the fastest planes but seen to be fleet long back i.e. in 2003. These were banned when a fatal crash had been reported. And now are only found in the museums.  

7 0
3 years ago
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