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3 years ago

Whats the answer to Q=1/2p+15

1 answer:

6 0

Simplify 1/2p to p/2

subtract 15 from both sides

multiply both sides by 2

regroup terms

switch sides

Answer: p = 2(q - 15)

You might be interested in

What are 9 mulitples of 13

vagabundo [1.1K]

Answer:

See below

Step-by-step explanation:

13*1 = 13

13*2 = 26

13*3 = 39

13*4 = 52

13*5 = 65

13*6 = 78

13*7 = 91

13*8 = 104

13*9 = 117

13*10 = 130

3 0

3 years ago

Read 2 more answers

Alan needs to read 4 novels each month Let N be the number of novels Alan needs to read in M months. Write an equation relating

MaRussiya [10]

Answer:

T=N*M and he needs to read 44 books.

Step-by-step explanation:

Note: Let T represent the total amount of books that Alan needs to read in 11 months.

If we plug in the information we have been given we will find the total:

T=N*M

T=4*11

T=44

Alan has to read 44 books within a 11 month period.

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6 0

3 years ago

the perimeter of a picture frame is 24 inches if the width of the picture frame 5 inches what is the length of the picture frame

Ket [755]

You would divide 24 by 5 so the length would end up being: 4.8 in
Hope it helps!

7 0

3 years ago

A) What is the median of the given data?

maks197457 [2]

Answer:

The median is 190

Step-by-step explanation:

Answer is quite easy

6 0

3 years ago

Water is leaking out of an inverted conical tank at a rate of 6800.0 cubic centimeters per min at the same time that water is be

m_a_m_a [10]

Answer:

6.82 $mt^3/min$

Step-by-step explanation:

By congruence of triangles, the radius r of the cone base when its height is 1 meter satisfies the relation

r/1 = 2.5/6

(See picture attached)

So, r = 0.4166 meters when the water is 1 meter high.

The volume of a cone with radius of the base = R is given by

$V=\frac{\pi R^2h}{3}$

So, the volume of water when it is 1 meter high is

$V=\frac{\pi* 0.(4166)^2}{3}=0.1817\;mt^3$

One minute later, the height of the water is 1 meter + 30 centimeters = 1.30 mt

The radius now satisfies

r/1.3 = 2.5/6

and now the radius of the base is

r = 0.5416 mt

and the new volume of water is $0.3071\;mt^3$

So, the water is raising at a speed of

0.3071-0.1871 = 0.12 $mt^3/min$

This speed equals the difference between the water being pumped and the water leaking,

So,

<em>0.12 = Speed of water being pumped -6.8 </em>

and

Speed of water being pumped = 6.8+0.12 = 6.82 $mt^3/min$

8 0

2 years ago