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levacccp [35]
3 years ago
7

Which statement is a valid conclusion about the activation energy of the reverse reaction if the forward reaction is exothermic?

Chemistry
1 answer:
babunello [35]3 years ago
4 0

Answer:

e) The activation energy of the reverse reaction is greater than that of the forward reaction.

Explanation:

  • Activation energy is the minimum amount of energy that is required by the reactants to start a reaction.
  • An exothermic reaction is a reaction that releases heat energy to the surrounding while an endothermic reactions is a reaction that absorbs heat from the surrounding.
  • <em><u>In reversible reactions, when the forward reaction is exothermic it means the reverse reaction will be endothermic, therefore the reverse reaction will have a higher activation energy than the forward reaction.</u></em> The activation energy of the reverse reaction will be the sum of the enthalpy and the activation energy of the forward reaction.
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Calculate the mols for 4.2g of a Mg<br>​
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Answer:

0.175mol

Explanation:

Mole of a substance can be calculated using the formula as follows:

number of moles (n) = mass (m) ÷ molar mass (MM)

According to this question, there are 4.2g of Magnesium (Mg).

Molar mass of Magnesium = 24g/mol, hence, the number of moles of 4.2g of Mg is as follows:

n = 4.2g ÷ 24g/mol

n = 0.175mol

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At a given temperature, the elementary reaction A ---&gt;B in the forward direction is first order in A with a rate constant of
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Answer:

The value of the equilibrium constant for the reaction A ⇒ B is Kc = 1.72 × 10³.

The value of the equilibrium constant for the reaction B ⇒ A is K'c = 5.81 × 10⁻⁴.

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For the reaction A ⇒ B, the equilibrium constant (Kc) is equal to the forward rate constant (kf) divided by the reverse rate constant (ki).

Kc=\frac{kf}{ki} =\frac{1.60 \times 10^{2} s^{-1}   }{ 9.30 \times 10^{-2} s^{-1}} =1.72 \times 10^{3}

If we consider the inverse reaction B ⇒ A, its equilibrium constant (K'c) is the inverse of the forward reaction equilibrium constant.

K'c=\frac{1}{Kc} =\frac{1}{1.72 \times 10^{3}  } =5.81 \times 10^{-4}

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