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pishuonlain [190]
3 years ago
13

Where do objects becomes weightless and why?

Physics
2 answers:
san4es73 [151]3 years ago
6 0
Object become weightless in space and in water. gravity is what holds an object down, without gravity object would float around.
Fed [463]3 years ago
5 0
           Weight = (mass) x (local acceleration of gravity)

The local acceleration of gravity depends on the other masses
around you and your distance from them.  So an object can only be
truly weightless when it's infinitely far away from any other mass.

But an object appears to be weightless when it's in free fall, that is,
when the only force acting on it is the force of gravity.  In that situation,
the sensation of 'weight' is impossible ... you can never feel that something
is pressing against you, because everything else is also in free fall. 
So a scale on the floor can't exert force against your feet, the mattress
on your bed can't exert force against your back, and your heart, liver,
stomach and spleen can't exert force against your other guts. 
Nothing seems to have weight, because everything is falling with
the same acceleration. 
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sasho [114]

Answer:

The answer is 40 cm.

Explanation:

7 0
3 years ago
Why polarized sunglasses particularly effective in reducing glare?
kipiarov [429]

Answer:

Polarized glasses contains a special filter that block dangerous intensity of lights which are reflected by flat surfaces and they help in reducing glare and discomfort

Explanation:

Sunlight scatters in all the direction. But when this light strikes with the flat surfaces, then the light which is reflected by the flat surface tend to become polarized, means the reflected light will travel in all directions. This reflecting light creates a dangerous intense light that causes glare and reduces visibility.

Polarized glasses contains a special filter that block this type of dangerous intensity lights, help in reducing glare and discomfort.

Therefore, by the above discussion it can be say that the polarized sunglasses particularly effective in reducing glares.

8 0
3 years ago
When does a skydiver achieve terminal velocity? when gravity equals air resistance when gravity is greater than air resistance w
ElenaW [278]

Answer:

when gravity equals air resistance

Explanation:

There are two forces acting on a skydiver falling down:

1) Gravity - this force acts downward, and it is constant during the whole fall, because its magnitude is given by

F=mg

where m is the mass of the skydiver and g the gravitational acceleration. Both quantities are constant, so the force of gravity is constant.

2) Air resistance - this force acts upward, and it is not constant: it is proportional to the velocity of the skydiver

F=kv

where k is a constant and v is the velocity. Therefore, as the skydiver falls down, its velocity increases and the air resistance increases as well.


The equation of forces for the skydiver is therefore:

mg-kv=ma

where a is the skydiver's acceleration. At the beginning of the fall, mg>kv, so the skydiver accelerates towards the ground. However, as he accelerates, the air resistance kv increases, till the moment at which air resistance becomes equal to gravity:

mg=kv

when this condition occurs, then the acceleration becomes zero, so the skydiver no longer accelerates and continues his fall at constant speed. This constant speed is called terminal velocity, and so it occurs when

gravity equals air resistance

3 0
3 years ago
Read 2 more answers
If a powerlifter raises a 1000 N weight a distance of 2.0 meters in 0.5 seconds, what is his power output?
Ilya [14]
Power =Force * Velocity

Velocity = Distance/Time = 2/0.5 = 4 m/s

Therefore,

P = 1000*4 =  4000 W = 4 kW
3 0
3 years ago
Read 2 more answers
The distance between two telephone poles is 50 m. A 1 kg bird lands on the telephone wire midway between the poles, and the wire
masha68 [24]

Answer:

the tension produce by the bird in the wire is 610.3 N.

Explanation:

given information:

mass of the bird, m = 1 kg

distance of two telephone pole, L = 50 m

wire sag, y = 0.2

the tension of the wire can be calculate by the following equation

tan θ = y/(L/2)

         = 0.2/(50/2)

         = 0.2/25

thus

θ = arc tan (0.2/25)

  = 0.46°

according to Newton's first law

ΣF = 0, vertical direction

T sin θ + T sin θ - mg = 0

2 T sin θ = m g

T = mg/2 sinθ

  = 1 x 9.8/(2 sin 0.46)

  = 610.3 N

3 0
4 years ago
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