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3 years ago

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In his version of the periodic table, mendeleev based his arrangement of the elements on an element's _________. atomic number c

hemical symbol atomic mass name

1 answer:

sammy [17]3 years ago

4 0

ʜᴇʟʟᴏ ᴛʜᴇʀᴇ!

In his version of the periodic table, Mendeleev based his arrangement of the elements on an element's atomic mass.

нσρє тнιѕ нєℓρѕ уσυ!
gσσ∂ ℓυ¢к :)
нανє α gяєαт ∂αу

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A helium-filled balloon at 310.0 K and 1 atm, contains 0.05 g He, and has a volume of 1.21 L. It is placed in a freezer (T = 235

trapecia [35]

Answer : The value of $\Delta E$ of the gas is 2.79 Joules.

Explanation :

First we have to calculate the moles of helium.

$\text{Moles of helium}=\frac{\text{Mass of helium}}{\text{Molar mass of helium}}$

Molar mass of helium = 4 g/mole

$\text{Moles of helium}=\frac{0.05g}{4g/mole}=0.0125mole$

Now we have to calculate the heat.

Formula used :

$q=nc_p\Delta T\\\\q=nc_p(T_2-T_1)$

where,

q = heat

n = number of moles of helium gas = 0.0125 mole

$c_p$ = specific heat of helium = 20.8 J/mol.K

$T_1$ = initial temperature = 310.0 K

$T_2$ = final temperature = 235.0 K

Now put all the given values in the above formula, we get:

$q=nc_p(T_2-T_1)$

$q=(0.0125mole)\times (20.8J/mol.K)\times (235.0-310.0)K$

$q=-19.5J$

Now we have top calculate the work done.

Formula used :

$w=-p\Delta V\\\\w=-p(V_2-V_1)$

where,

w = work done

p = pressure of the gas = 1 atm

$V_1$ = initial volume = 1.21 L

$V_2$ = final volume = 0.99 L

Now put all the given values in the above formula, we get:

$w=-p(V_2-V_1)$

$w=-(1atm)\times (0.99-1.21)L$

$w=0.22L.artm=0.22\times 101.3J=22.29J$

conversion used : (1 L.atm = 101.3 J)

Now we have to calculate the value of $\Delta E$ of the gas.

$\Delta E=q+w$

$\Delta E=(-19.5J)+22.29J$

$\Delta E=2.79J$

Therefore, the value of $\Delta E$ of the gas is 2.79 Joules.

3 0

3 years ago

The atmosphere is composed of

allsm [11]

I think it's the c (<span>.all the gases that surround the Earth)</span>

8 0

3 years ago

1. What is different about the way molecules move in liquids?

mel-nik [20]

Answer:

me donno

Explanation:

4 0

3 years ago

Read 2 more answers

1. A sample of aluminum absorbs 50.1 J of heat, upon which the temperature of the sample increases from 20.0°C to 35.5°C. If the

Maurinko [17]

Answer:

Mass of aluminium in sample = 3.591 g ≅ 3.6 grams

Explanation:

Given that, A sample of aluminum absorbs 50.1 J of heat, upon which the temperature of the sample increases from 20.0°C to 35.5°C.

the specific heat of aluminum is 0.900 J/g- °C

The relation between heat absorbed and change in temperature is given by, Q = msΔT.

where Q = heat absorbed

m = mass of the substance

s = specific heat of substance

ΔT = change in temperature

Now, in our case, Q = 50.1 J ; s = 0.900 J/g- °C; ΔT= 35.5-20 = 15.5°C

⇒ m = $\frac{Q}{s(T_{2} -T_{1}) }$

⇒ m = $\frac{50.1}{0.900(15.5)}$ = 3.591 g ≅ 3.6 g

⇒ m ≅ 3.6 g

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3 years ago

Which of the followings are not the receptor

Ludmilka [50]

I believe it’s cold receptor

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2 years ago