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3 years ago

Please please help i have to turn in

Physics

1 answer:

larisa [96]3 years ago

6 0

Hi,

I've found a link that should assist you or answer your question.
http://click.dji.com/ANbvbbP7bwUWtSACp6U_?pm=link&as=0004

Have a nice day!

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Please help, im stuck on this question

saw5 [17]

Answer:

A) .27 A

Explanation:

v = ir

i = v/r

equivalent r = 45 * 90 / (45+90) = 30 ohms ( for the two r in parallel)

i = 8v / 30 ohm = 267 mAmps

8 0

2 years ago

g In 1956, Frank Lloyd Wright proposed the construction of a mile-high building in Chicago. Suppose the building had been constr

Lorico [155]

To solve this problem it is necessary to apply the concepts related to acceleration due to gravity, as well as Newton's second law that describes the weight based on its mass and the acceleration of the celestial body on which it depends.

In other words the acceleration can be described as

$a = \frac{GM}{r^2}$

Where

G = Gravitational Universal Constant

M = Mass of Earth

r = Radius of Earth

This equation can be differentiated with respect to the radius of change, that is

$\frac{da}{dr} = -2\frac{GM}{r^3}$

$da = -2\frac{GM}{r^3}dr$

At the same time since Newton's second law we know that:

$F_w = ma$

Where,

m = mass

a =Acceleration

From the previous value given for acceleration we have to

$F_W = m (\frac{GM}{r^2} ) = 600N$

Finally to find the change in weight it is necessary to differentiate the Force with respect to the acceleration, then:

$dF_W = mda$

$dF_W = m(-2\frac{GM}{r^3}dr)$

$dF_W = -2(m\frac{GM}{r^2})(\frac{dr}{r})$

$dF_W = -2F_W(\frac{dr}{r})$

But we know that the total weight (F_W) is equivalent to 600N, and that the change during each mile in kilometers is 1.6km or 1600m therefore:

$dF_W = -2(600)(\frac{1.6*10^3}{6.37*10^6})$

$dF_W = -0.3N$

Therefore there is a weight loss of 0.3N every kilometer.

4 0

4 years ago

Can someone help me asap, please?

Anon25 [30]

Answer:

kinetic energy, form of energy that an object or a particle has by reason of its motion.

potential energy, stored energy that depends upon the relative position of various parts of a system

6 0

2 years ago

A bicyclist is riding to the left with a velocity of 14 \,\dfrac{\text m}{\text s}14 s m 14, start fraction, start text, m, en

Gnesinka [82]

Answer:

-2.0 m/s²

Explanation:Acceleration is the rate of change of velocity.

\begin{aligned}a&=\dfrac{\text{Change in velocity}}{\text{Change in time}}\\ \\ &=\dfrac{v_f-v_i}{\Delta t} \end{aligned}

Change in time

Change in velocity

Δt

−v

Hint #22 / 3

We can calculate the bicyclist's acceleration from the final velocity v_fv

v, start subscript, f, end subscript, initial velocity v_iv

v, start subscript, i, end subscript, and time interval \Delta tΔtdelta, t.

\begin{aligned}a&=\dfrac{v_f-v_i}{\Delta t}\\ \\ &=\dfrac{-21\,\dfrac{\text m}{\text s}-(-14\,\dfrac{\text m}{\text s})}{3.5\,\text s}\\ \\ &=-2.0\,\dfrac{\text m}{\text s^2}\end{aligned}

Δt

−v

3.5s

−21

−(−14

)

=−2.0

Hint #33 / 3

The acceleration of the bicyclist is -2.0\,\dfrac{\text m}{\text s^2}−2.0

minus, 2, point, 0, start fraction, start text, m, end text, divided by, start text, s, end text, squared, end fraction.

5 0

3 years ago

Which is the term used for a change in the magnitude of the velocity

Alborosie

Rate of change of velocity is called acceleration. When this rate of change is constant, it is called uniform acceleration. Like the change of velocity of an object falling freely under gravity. Its velocity increases by 9.8 m every second. This acceleration is denoted as 9.8m/s^2

8 0

3 years ago