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Aneli [31]
3 years ago
7

How many days are in a year on mars

Physics
1 answer:
Triss [41]3 years ago
7 0
687 days
hope this helps
stay safe
brainliest is appreciated
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What will happen if you rub two different materials together?
Dafna1 [17]
It will cause heat from friction
6 0
3 years ago
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A child on a skateboard experiences a 75 N force with an acceleration of 1.5 m/s2.
cupoosta [38]

Answer:

The mass of the child + skateboard is 50 kg

Explanation:

In this problem, we can apply Newton's second law:

F = ma

where

F is the net force on a system

m is the mass of the system

a is the acceleration of the system

In this problem, our system is the child + the skateboard. The net force on them is

F = 75 N

and their acceleration is

a=1.5 m/s^2

So we can re-arrange the equation above to find their combined mass:

m=\frac{F}{a}=\frac{75}{1.5}=50 kg

3 0
3 years ago
If objects at the same distance suddenly decreased in mass the gravitational force between them would
inn [45]

Answer:

The Gravitational force would decrease

Explanation:

To calculate FG the formula is:

Fg=mg

if mass decreases then the gravitational force would decrease

5 0
3 years ago
Convert 15 joule into erg.​
GuDViN [60]

Answer:

<h2><u>Joule</u><u>:</u></h2>

1 Joule of work is said to be done when a force of 1 Newton is applied to move/displace a body by 1 metre.

1 Joule= 1 Newton × 1 metre

1 Newton is the amount of force required to accelerate body of mass 1 kg by 1m/s²

So units of N is kgm/s²

So,

1 Joule

=1kgm/s² × m

=1kgm²/s²

<h2><u>Erg</u><u>:</u></h2>

1 erg is the amount of work done by a force of 1 dyne exerted for a distance of one centimetre.

1 Erg =1 Dyne × 1 cm

1 dyne is the force required to cause a mass of 1 gram to accelerate at a rate of 1cm/s².

1 Erg=1 gmcm/s² × cm

1 Erg=1 gmcm/s² × cm=1gmcm²/s²

this is what you need to convert 1gmcm²/s² to 1kgm²/s²

<h3><u>what you need to know for conversion</u></h3>

[1gm=0.001kg

1cm²

=1cm ×1cm

=0.01 m × 0.01 m

=0.0001m²

second remains constant

]

So,

1gmcm²/s²

=0.001kg×0.0001m²/s²

=0.001kg×0.0001m²/s² =0.0000001kgm²/s²

Hence,

<h3><u>1 Erg</u><u>=</u><u>0.0000001</u><u> </u><u>Joule</u></h3><h3><u>1</u><u> </u><u>Joule</u><u>=</u><u>1</u><u>0</u><u>,</u><u>0</u><u>0</u><u>0</u><u>,</u><u>0</u><u>0</u><u>0</u><u> </u><u>Erg</u></h3>

<h2>⇒15 J=15×10000000 Erg</h2><h2> =150000000 Erg</h2><h2> =1.5×10⁶ Erg</h2>
3 0
3 years ago
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With what speed would mail pass through the center of the Moon if falling in a tunnel that runs through the center
ratelena [41]

Answer:

$v_f = = 7.9 \times10^3 \text{ m/s }$

7 0
3 years ago
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