The answer is A :) hope this help
Answer:
Pyridine solution has a greater concentration of hydroxide ions.
Explanation:
The pOH of the solution is defined as negative logarithm of hydroxide ion concentration in a solution.
![pOH=-\log [OH^-]](https://tex.z-dn.net/?f=pOH%3D-%5Clog%20%5BOH%5E-%5D)
- Higher the value of pOH lessor will be the hydroxide ion concentration and higher the concentration of hydrogen ions in the solution .
- Lower the value of pOH higher will be the hydroxide ion concentration and lower the concentration of hydrogen ions in the solution.
1) The pOH of the methylamine = 6.8
![6.8=-\log[OH^-]](https://tex.z-dn.net/?f=6.8%3D-%5Clog%5BOH%5E-%5D)
![[OH^-]=1.5848\times 10^{-7} M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D1.5848%5Ctimes%2010%5E%7B-7%7D%20M)
2) The pOH of the pyridine = 6.0
![6.0=-\log[OH^-]](https://tex.z-dn.net/?f=6.0%3D-%5Clog%5BOH%5E-%5D)
![[OH^-]=0.000001 M=1.0\times 10^{-6} M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D0.000001%20M%3D1.0%5Ctimes%2010%5E%7B-6%7D%20M)
Pyridine solution has a greater concentration of hydroxide ions than the solution of methylamine.