The answer is; the density of the liquid suppresses the height to which it can rise
The density acts in the opposite direction of capillary action. Capillary action allows the liquid to rise in the tube and the narrower the tube the higher the capillary action and the higher the liquid rises. The denser the liquid however, the lower it will rise. The column stops rising when the capillary force is balanced by the weight of the rising liquid due to gravity.
Answer:
t = 23.255 s, x = 2298.98 m, v_y = - 227.90 m / s
Explanation:
After reading your extensive writing, we are going to solve the approach.
The initial speed of the plane is 250 miles / h and it is at an altitude of 2650 m; In general, planes fly horizontally for launch, therefore this is the initial horizontal speed.
As there is a mixture of units in different systems we are going to reduce everything to the SI system.
v₀ₓ = 250 miles h (1609.34 m / 1 mile) (1 h / 3600 s) = 111.76 m / s
y₀ = 2650 m
Let's set a reference system with the x-axis parallel to the ground, the y-axis is vertical. As time is a scalar it is the same for vertical and horizontal movement
Y axis
y = y₀ + v₀ t - ½ g t²
the initial vertical velocity when the cargo is dropped is zero and when it reaches the floor the height is zero
0 = y₀ + 0 - ½ g t²
t =
t = √(2 2650/ 9.8)
t = 23.255 s
Therefore, for the cargo to reach the desired point, it must be launched from a distance of
x = v₀ₓ t
x = 111.76 23.255
x = 2298.98 m
at the point and arrival the speed is
vₓ = v₀ₓ = 111.76
vertical speed is
v_y = v_{oy} - gt
v_y = 0 - gt
v_y = - 9.8 23.25 555
v_y = - 227.90 m / s
the negative sign indicates that the speed is down
in the attachment we have a diagram of the movement
An element is a pure substance that cant be broken down into simpler substances by chemical or physical means. hope it helps :)
Answer:
A los 10 segundos su velocidad será 15 
Explanation:
La aceleración de un objeto es una magnitud que indica cómo cambia la velocidad del objeto en una unidad de tiempo.
En otras palabras, la aceleración relaciona los cambios de la velocidad con el tiempo en el que se producen, es decir que mide cómo de rápidos son los cambios de velocidad:
- Una aceleración grande significa que la velocidad cambia rápidamente.
- Una aceleración pequeña significa que la velocidad cambia lentamente.
- Una aceleración cero significa que la velocidad no cambia.
La aceleración "a" puede ser calculada mediante la expresión:

En este caso:
- a= 1

- vfinal= ?
- vinicial= 5

- tiempo= 10 s
Reemplazando:

Resolviendo se obtiene:
1
*10 s= vfinal - 5 
10
= vfinal - 5 
10
+ 5
= vfinal
15
= vfinal
<u><em>A los 10 segundos su velocidad será 15 </em></u>
<u><em></em></u>
Answer:
A and C is about 12 cm away from each other.
Explanation: