2 years ago

PbCl2s) + Cl2g - + PbCl40) ΔΗ = ?

1 answer:

4 0

Answer:

ichedgepeth

Explanation:

beginner because it's tough than other things

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serg [7]

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denpristay [2]

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AlladinOne [14]

Answer:

Explanation:

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Ostrovityanka [42]

Explanation: This is a reaction of oxidation of $H_2O_2$ in the presence of acidified $KMnO_4$ . Acidified $KMnO_4$ is a strong oxidizing agent.

To balance out the $H^+$ on the reactant side, we write $H_2O$ on the product side.

Balancing out the following reaction gives us:

$2MnO_4^-+6H^++5H_2O_2\rightarrow 2Mn^{2+}+8H_2O+5O_2$

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3 years ago

kirza4 [7]

4.0 +4.0= 8.0

8.0+8.0=16.0

16.0+16.0=32.0

32.0+32.0=64.0

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3 years ago