Answer:
40.0 L.
Explanation:
- We can use the general law of ideal gas: <em>PV = nRT.</em>
where, P is the pressure of the gas in atm.
V is the volume of the gas in L.
n is the no. of moles of the gas in mol.
R is the general gas constant,
T is the temperature of the gas in K.
- If P and T are constant, and have different values of n and V:
<em>(V₁n₂) = (V₂n₁).</em>
V₁ = 50.0 L, n₁ = 2.0 moles,
V₂ = ??? L, n₂ = 2.0 mol - 0.4 mol = 1.6 mol.
∴ V₂ = (V₁n₂)/(n₁) = (50.0 L)(1.6 mol)/(2.0 mol) = 40.0 L.
Answer:
C- Using a 0.35 g sample of Li(s) cut into smaller pieces will increase the rate of reaction
C- Equal quantities of gas will be produced with potassium K, used instead of Lithium, Li.
Explanation:
<u>First part</u>
When a metal is present in small pieces, the rate of the chemical reaction increases. This is due to small pieces provide more surface area for reaction than huge chunks of Li.
moles of reactant decreases product formation rate also decreases and temperature decreases rate also decreases so remaining option are wrong
<u>Second part
</u>
2Li + 2H2O --------------> 2LiOH + H2
2K + 2H2O ---------------> 2KOH + H2
Hence, both gives same quantity of gas
Explanation:
carbon dioxide waste from the body, is a result of
cellular metabolism. Through exhalation, a body gets rid of CO2. (the lungs), are most important in removal of co2.
10) cellular transport through the lungs.
11) o2 (inhalation) lungs, oxygenate cells to deliver o2 through the bloodstream to perform proper function. plus the pulmonary arteries renew and release CO2 from the body..
Complete Question:
Ions to calculate the p-values: Na⁺, Cl⁻, and NH₄⁺
Answer:
pNa = 0.307
pCl = 0.093
pNH₄ = 0.503
Explanation:
The p-value is calculated by the antilog of the concentration of the substance of interest. For example, pH = -log[H⁺]. Thus, first, let's find the ions concentration.
Both substances are salts that solubilize completely, thus, by the solution reactions:
NaCl → Na⁺ + Cl⁻
NH₄Cl → NH₄⁺ + Cl⁻
So, for both reactions the stoichiometry is 1:1:1 and the concentration of the ions is equal to the concentration of the salts.
[Na⁺] = 0.493 M
[Cl⁻] = 0.493 + 0.314 = 0.807 M
[NH₄⁺] = 0.314 M
The p-values are:
pNa = -log[Na⁺] = -log(0.493) = 0.307
pCl = -log[Cl⁻] = -log(0.807) = 0.093
pNH₄ = -log[NH₄⁺] = -log(0.314) = 0.503
