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NikAS [45]
3 years ago
7

Arrange the molecules H2O, NH3, Ar, NaCl in order of expected increasing boiling points. 1. None of these 2. NaCl, H2O, NH3, Ar

3. Ar, NH3, H2O, NaCl 4. NH3, Ar, H2O, NaCl
Chemistry
1 answer:
Aleks04 [339]3 years ago
4 0

Answer:

Option (4) is correct

Explanation:

  • NaCl is an ionic solid. Na^{+} and Cl^{-} ions are held together by strong coloumbic attractive force. Hence NaCl has highest boiling point'
  • Ar is a monoatomic molecule. Hence only weak london dispersion force exists between Ar atom/molecules. Hence it requires lowest amount of energy to boil and thereby possess lowest boiling point.
  • NH_{3} and H_{2}O are polar protic molecules. Hence they possess london dispersion force, dipole-dipole force and hydrogen bonding as intermolecular forces.
  • Dipole-dipole force is stronger in H_{2}O than NH_{3} due to more polar O-H bond than N-H bond. Also molecular weight of H_{2}O is higher than NH_{3}. So, more energy is required to boil H_{2}O. So, H_{2}O has higher boiling point than NH_{3}

Hence order of boiling point : NaCl>H_{2}O>NH_{3}>Ar

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K = °C + 273 A 4.1 L sample of gas is held at 25 °C. If the gas expands to 6.8 L, what is the final temperature?
gregori [183]

Answer:

221 °C

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 4.1 L

Initial temperature (T₁) = 25 °C

= 25 °C + 273

= 298 K

Final volume (V₂) = 6.8 L

Final temperature (T₂) =?

The final temperature of the gas can be obtained as follow:

V₁ / T₁ = V₂ / T₂

4.1 / 298 = 6.8 / T₂

Cross multiply

4.1 × T₂ = 298 × 6.8

4.1 × T₂ = 2026.4

Divide both side by 4.1

T₂ = 2026.4 / 4.1

T₂ ≈ 494 K

Finally, we shall convert 494 K to celcius temperature. This can be obtained as follow:

°C = K – 273

K = 494

°C = 494 – 273

°C = 221 °C

Thus the final temperature of the gas is 221 °C

6 0
3 years ago
How many joules of heat are lost when 150.0 g of steam are cooled from 124. C to 86 C?
Alinara [238K]

 The  amount   of  joules  of heat  that are lost when 150.0 g of steam  are cooled  from 124 °c to 86 °c  is = -11343  joules


 calculation

heat(Q) = mass(m) x specific heat capacity(C) x  change  in temperature     (ΔT)

  where,

Q=? joules

M=150.0 g

C for steam = 1.99 j/g/°c

ΔT= 86°c-124°c = -38°c


Q  is therefore = 150.0 g x  1.99 j/g/°c   x -38°c =-11343 joules


6 0
3 years ago
) The reaction below is exothermic: 2SO2 (g) O2 (g) 2SO3 (g) Le Cha^ telier's Principle predicts that __________ will result in
Lynna [10]

Answer:

A) increasing the pressure

Explanation:

Given the exothermic reaction:

2SO₂(g) + O₂(g) ↔  2SO₃(g)

the question asks what will make the number of moles of SO₃(g) to increase.

When an equilibrium is disturbed, the system will shift in order to counteract the change (see <em>Le Chatelier's Principle</em>) So <em>when the pressure is increased in a reaction involving gases, the equilibrium will shift trying to decrease the number of moles </em>(because pressure is produced by molecules hitting the container), that is in this case it will shift towards the right side, towards the production of SO₃, thus increasing the number of moles of SO₃.

The number of moles in the right side is 2 and the number of moles in the left side is 3.

3 0
3 years ago
Consider the reaction: 2clf3(g) + 2nh3(g) → n2(g) + 6hf(g) + cl2(g) when calculating the δh°rxn, why is the δhf° for n2 not impo
Leni [432]

<span>Actually, the heat of reaction hrxn s calculated by taking the sum of the heats of formation of the products minus the sum of the heats of formation of the reactants. However, at heat of formations of pure elements at atmospheric conditions is zero, therefore the hf of N2 is not important since it is zero anyway.</span>

8 0
3 years ago
How many moles is 2.2 x 1023 atoms of Fe?
kow [346]

Answer:

it's 3.77 moles

Explanation:

Pls give brainliest :)

4 0
3 years ago
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