|Ω| = 6 - number of all results
A = {1, 3} → |A| = 2 - number of (a) results
P(A) = 2/6 = 1/3
Yes you can simplify an improper fraction
Polynomials can have double roots, in fact they're pretty common. if you get a reasonable zero it costs very little time to try it again for a double root. answer is the second choice
N - 5 ≥ -2
5 - 5 ≥ -2
5 - 5 = 0
n = 5
5 - 5 ≥ -2
5 - 5 = 0
(0 ≥ -2)