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stiv31 [10]
3 years ago
10

Joe the house painter stands on a uniform oak board weighing 600 N and held up by vertical ropes at each end. Joe has been dieti

ng, and now weighs 844 N. The length of the board is 4.00 m, and Joe is standing 1.00 m from the left end of the board. What is the tension in each of the supporting ropes?

Physics
1 answer:
Mamont248 [21]3 years ago
3 0

Answer

given,

weight of the oak board = 600 N

Weight of Joe = 844 N

length of board = 4 m

Joe is standing at 1 m from left side

vertical wire is supporting at the end.

Assuming the system is in equilibrium

T₁ and T₂ be the tension at the ends of the wire

equating all the vertical force

T₁ + T₂ = 600 + 844

 T₁ + T₂ = 1444...........(1)

taking moment about T₂

 T₁ x 4 - 844 x 3 - 600 x 2 = 0

 T₁ x 4 = 3732

 T₁ = 933 N

from equation (1)

 T₂ = 1444 - 933

 T₂ = 511 N

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Autobus porusza się ze stałą prędkością 54 km/h Oblicz w jakim czasie przebędzie drogę 450 m

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2 years ago
An object is falling downward at a rate of 25 m/s. Two seconds later, what is its acceleration?
zhenek [66]

acceleration times time falling

25*2

50 m*s^-1

6 0
3 years ago
14) A race car accelerates from rest to a velocity of 41 m/s in 480 m. What is the acceleration of the race car?
natka813 [3]

Answer:

Explanation:

V₀ = 0 m/s

V = 41 m/s

S = 480 m

___________

a - ?

Distance traveled:

S =  (V² - V₀²) / (2*a)

Acceleration :

a = (V² - V₀²) / (2*S)

a = (41² - 0²) / (2*480) = 1.75 m/s²

8 0
1 year ago
A 56.0kg ice skater spins about a vertical axis through her body with her arms horizontally outstretched, making 2.50 turns each
Arada [10]

Answer:

Net force = 129.4, Force as multiple of weight of her hand = 18.84

Explanation:

Given Data:

Total body weight = 56.0 kg   ;

no. of turns = 2.5/second        ;

hand to hand distance = 1.5m ;

weight of hand = 1.25% of body weight ;

Solution:

mass of hand = \frac{1.25}{100}*56 = 0.7kg ;

radius = d/2 = 1.5/2 = 0.75m     ;

Now we need to find velocity, as we know that velocity can be calculated by dividing distance by time

v = d/t = \frac{2.5*2*3.14*0.75}{1} = 11.775 m/s or 12 m/s;

a.

The formula to calculate force is given as

F = mv²/r = (0.7*11.775²)/0.75 = 129.4 N

b.

To calculate force as multiple of weight on her hand, we need to calculate the gravitational force W on her hand first.

W = gm = 9.81 * 0.7 = 6.867 N

Now the wieght on her hand can be represented by

\frac{Force_{net} }{weight of hand}  = 129.4 / 6.867 = 18.84

3 0
3 years ago
A person is using a rope to lower a 5.0-n bucket into a well with a constant speed of 2.0 m/s. What is the magnitude of the forc
OLga [1]

Answer:

5 N

Explanation:

The bucket is moving at a constant speed of 2m/s Therefore F=ma is 0 N for this to be correct the magnitude of the force exerted by the rope must be equal to the weight of the bucket which is 5 N

7 0
3 years ago
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