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3 years ago

_____ numbers are based on the distribution of electrons in a molecule.

Chemistry

1 answer:

leva [86]3 years ago

8 0

Answer:

oxidation

Explanation:

oxidation number are based on the distribution of electrons in a molecule

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Below is a word equation. Please follow directions for each part below.

alukav5142 [94]

Answer:

CH3OH + 02 ----> C02 + H20

balanced equation -

CH3OH + 3/202 ----> C02 + 2H20

Use exactly the same process as the one used on another question of yours I answered.

8 0

2 years ago

Use Boyle's Law to explain what would happen to the volume of a helium- filled balloon if it was carried underwater by a diver t

oksano4ka [1.4K]

The deeper the diver takes the helium balloon, the more it reduces in size. This is due to the pressure of the water column above pressing on the balloon. According to Boyle’s law (P= k*1/V.), as the volume of the balloon decreases, the pressure of the helium inside increases.

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3 years ago

In solid NaCl, the equilibrium separation between neighboring Na+ and Cl- ions is 0.283 nm. Calculate the coulombic energy betwe

const2013 [10]

Explanation:

It is given that r = 0.283 nm. As 1 nm = $10^{-9} m$ .

Hence, 0.283 nm = $0.283 \times 10^{-9} m$

Formula for coulombic energy is as follows.

$U_{coulomb} = -1.748 \frac{e^{2}}{4 \pi \epsilon_{o} r}$

where, e = $1.6 \times 10^{-19}$ C

$\epsilon_{o}$ = $8.85 \times 10^{-12}$

$U_{coulomb} = -1.748 \frac{(1.6 \times 10^{-19}^{2}}{4 \times 3.14 \times 8.85 \times 10^{-12} \times 0.283 \times 10^{-9}}$

= $1.423 \times 10^{-18} J$

As 1 eV = $1.6 \times 10^{-19} J$

So, 1 J = $\frac{1 eV}{1.6 \times 10^{-19}}$

Hence, U = $\frac{1.423 \times 10^{-18} J}{1.6 \times 10^{-19} J}$

= 8.9 eV

Also, 1 J = $\frac{10^{-3} kJ}{6.022 \times 10^{23}mol}$

= $1.67 \times 10^{-27}$ kJ/mol

Therefore, U = $1.423 \times 10^{-18} J \times 1.67 \times 10^{-27}$ kJ/mol

= $2.37 \times 10^{-45} kJ/mol$

7 0

3 years ago

At a certain temperature, the vapor pressure of pure benzene ‍ is atm. A solution was prepared by dissolving g of a nondissociat

erastova [34]

Answer:

Molar mass of solute: 300g/mol

Explanation:

Vapor pressure of pure benzene: 0.930 atm

Assuming you dissolve 10.0 g of the non-volatile solute in 78.11g of benzene and vapour pressure of solution was found to be 0.900atm

It is possible to answer this question based on Raoult's law that states vapor pressure of an ideal solution is equal to mole fraction of the solvent multiplied to pressure of pure solvent:

$P_{sln} = X_{solvent}P_{solvent}^0$

Moles in 78.11g of benzene are:

78.11g benzene × (1mol / 78.11g) = 1 mol benzene

Now, mole fraction replacing in Raoult's law is:

0.900atm / 0.930atm = 0.9677 = moles solvent / total moles.

As mole of solvent is 1:

0.9677× total moles = 1 mole benzene.

Total moles:

1.033 total moles. Moles of solute are:

1.033 moles - 1.000 moles = 0.0333 moles.

As molar mass is the mass of a substance in 1 mole. Molar mass of the solute is:

10.0g / 0.033moles = 300g/mol

8 0

2 years ago

What is true of a strong acid? (3 points)

forsale [732]

The answer is A it’s ionizes in water

5 0

3 years ago

Read 2 more answers