Answer:
The solution becomes diluted.
Explanation:
When you add water to a solution, the number of moles of the solvent stays the same while the volume increases. Therefore, the molarity decreases.
Hope this helps!
Answer:
NH₃
Explanation:
mass H = 6.10 grams
mass N = 28.00 grams
mass cpd = (6.10 + 28.00)grams = 34.10 grams
%H/100wt = (6.10/34.10)100% = 17.9% w/w
%N/100wt = (28.00/34.1)100% = 82.1% w/w
%/100wt => grams/100wt => moles => ratio => reduce => emp ratio
%H/100wt = 17.9% w/w => 17.9g => (17.9/1)moles = 17.9 moles H
%N/100wt = 82.1% w/w => 82.1g => (82.1/14)moles = 5.9 moles N
Ratio N:H => 17.9 : 5.9
Reduce mole ratio (divide by smaller mole value) => 17.9/5.9 : 5.9/5.9
=> 3HY:1H empirical ratio => empirical formula NH₃ (ammonia)
1) Molarity
M = n / V
n: number of moles of solute
V: volume of the solution in liters
n = mass / molar mass = 0.000333 g / 332.32 g / mol = 1*10 ^ - 6 moles
V = 225 ml * 1 liter / 1000 ml = 0.225 liter
M = 10^-6 mol / 0.225 liter = 0.00000444 M
2) ppm
ppm = parts per million
grams of solute: 0.000333 g
grams of solution = volume * density = 225 ml * 0.785 g / ml = 176.625 g
ppm = [0.00033 g / 176.625 g] * 1,000,000 = 1.868 ppm
The oxygen which will be consumed by a person in 1 week is 393.75 moles.
The ratio of a substance's given mass in a chemical reaction to the mass of one mole of that material is the number of moles of that substance. A mole of any substance is equal to 6.023 × 10²³ or Avogadro's number. Molecular weight and other concentration units like mole per liter are also expressed using it.
No. of moles = given mass of substance / Molar mass of a substance
here, given mass = 900g
molar mass = 16g
No. of moles = 900/16 =56.25 moles
This means that 56.25 moles are consumed by a person in 1 day
No. of moles of oxygen consumed in 1 week = 56.25 ×7 = 393.75 moles
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Answer:
fomula; ( x = mutiplacation btw)
% m/m = m(solute) / m(solution) x 100%
0.50g x 70% = m/m x 100%
0.5g x 70% / 100% = 3.5 g KI
(both % cancle each other)
Explanation:
heads up might be wrong i did it myself