The number of oxygen atoms that are contained in 160 grams of N2O3 are 3.80 x10^24 atoms ( answer C)
<u><em>Explanation</em></u>
Step 1: calculate the moles of N2O3
moles= mass N2O3 /molar mass N2O3
molar mass of N2O3 = (14 x2) +( 16 x3) =76 g/mol
moles of N2O3 = 160 g/ 76 g/mol = 2.105 moles
Step 2: from the moles of N2O3 find the moles of Oxygen
=moles of N2O3 x number of oxygen atoms in N2O3( 3)
= 3 x 2.105 =6.315 moles
Step 3:use the Avogadro's law to calculate the atoms of oxygen
that is according to Avogadro's law 1 mole = 6.02 x10 ^23 atoms
6.315 moles= ? atoms
={ (6.315 moles x 6.02 x10 ^23 atoms) / 1 mole} =3.80 x10^24 atoms
