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3 years ago

8

If a freely falling rock were equipped with a speedometer, by how much would its speed readings increase with each second of fal

l?

1 answer:

Klio2033 [76]3 years ago

5 0

Its speed reading would increase to 10 m/s every second

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Using Rayleigh's criterion, what is the smallest separation between two pointlike objects that a person could clearly resolve at

atroni [7]

Answer:

y = 52.44 10⁻⁶ m

Explanation:

It is Rayleigh's principle that two points are resolved if the maximum of the diffraction pattern of one matches the minimum the diffraction pattern of the other

Based on this principle we must find the angle of the first minimum of the diffraction expression

a sin θ= m λ

The first minimum occurs for m = 1

sin θ = λ / a

Now let's use trigonometry the object is a distance L = 0.205 m

tan θ = y / L

Since the angles are very small, let's approximate

tan θ = sin θ/cos θ = sin θ

sin θ = y / L

We substitute in the diffraction equation

y / L = λ / a

y = λ L / a

Let's calculate

y = 550 10⁻⁹ 0.205 / 2.15 10⁻³

y = 52.44 10⁻⁶ m

7 0

3 years ago

A spring scale exerts a net force of 8.5 N on an object. What is the object's mass if it has an acceleration of

Amiraneli [1.4K]

Answer:

mass of the object is 2.18 kg

Explanation:

Given

Force (F) = 8.5 N = 8.5 kg.m/ $s^{2}$

acceleration (a) = 3.9 m/ $s^{2}$

Mass (m) = ?

We know that the newton's second law of motion gives the relation between mass of ab object. force acted upon and the amount the object is accelerated. It is expressed in the form of an equation:

F = ma

mass, m = F/a

= $\frac{8.5 kgms^{-2} }{3.9 ms^{-2} }$

= 2.18 kg

4 0

3 years ago

An object islaunched at velocity of 20 m/s in a direction making an angle of 25 degree upward with the horizontal. what is the m

Aneli [31]

Answer:

$\displaystyle y_m=3.65m$

Explanation:

<u>Motion in The Plane</u>

When an object is launched in free air with some angle respect to the horizontal, it describes a known parabolic path, comes to a maximum height and finally drops back to the ground level at a certain distance from the launching place.

The movement is split into two components: the horizontal component with constant speed and the vertical component with variable speed, modified by the acceleration of gravity. If we are given the values of $v_o$ and $\theta\\$ as the initial speed and angle, then we have

$\displaystyle v_x=v_o\ cos\theta$

$\displaystyle v_y=v_o\ sin\theta-gt$

$\displaystyle x=v_o\ cos\theta\ t$

$\displaystyle y=v_o\ sin\theta\ t -\frac{gt^2}{2}$

If we want to know the maximum height reached by the object, we find the value of t when $v_y$ becomes zero, because the object stops going up and starts going down

$\displaystyle v_y=o\Rightarrow v_o\ sin\theta =gt$

Solving for t

$\displaystyle t=\frac{v_o\ sin\theta }{g}$

Then we replace that value into y, to find the maximum height

$\displaystyle y_m=v_o\ sin\theta \ \frac{v_o\ sin\theta }{g}-\frac{g}{2}\left (\frac{v_o\ sin\theta }{g}\right )^2$

Operating and simplifying

$\displaystyle y_m=\frac{v_o^2\ sin^2\theta }{2g}$

We have

$\displaystyle v_o=20\ m/s,\ \theta=25^o$

The maximum height is

$\displaystyle y_m=\frac{(20)^2(sin25^o)^2}{2(9.8)}=\frac{71.44}{19.6}$

$\displaystyle y_m=3.65m$

7 0

2 years ago

The Kyoto protocol works by _______.

Lapatulllka [165]

The answer is voluntary involvement! :D Welcome

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3 years ago

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you arrive at an intersection with traffic lights that arent working because of a power outage .what do you do

ElenaW [278]

Use it as a four way stop.

6 0

3 years ago

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