All categories

2 years ago

What is mass times acceleration?

Physics

1 answer:

frozen [14]2 years ago

6 0

Answer:

Force

Explanation:

The mass of an object is the quantity of matter it contains. It is measured in kilograms.

Acceleration is the ratio of the change in the velocity of an object to the change in time. It is measured in m/ $s^{2}$ .

When the mass of an object is multiplied with its acceleration, this gives the average force applied on the object. As force is defined as agent that can change the state of an object.

i.e F = m × a

where F is the force, m is the mass of the object and a its acceleration.

The two major classes of force are; contact force and field force.

You might be interested in

Zeros are always considered significant digits when they are to the left of the decimal point

maksim [4K]

Answer:

Zeros to the left of a decimal can be insignificant place holders, such as in 0.043 (two significant figures).

They can be significant if they are between two digits who themselves are significant, such as in 101.000 (three significant figures).

In the case of a number like 1,000 we can see there is only one significant figure. The zero digits are not between sigfigs.

7 0

3 years ago

Why does a pencil look bent when it is placed in a glass of water?

Nonamiya [84]

Answer:

This is due to bending of light ray passing through the medium.

Explanation:

This can be explained using the concept of refraction.

Refraction can be defined as the bending of light ray as it travels from one medium to another (it can be from the less dense to denser medium or denser to less dense medium)

For that of pencil in water, light ray travels from less dense medium(surrounding air) to denser medium(water). This causes the pencil to bend away from the normal rather than towards the normal (angle of refraction being greater than angle of incidence) and hence the reason for the bending.

NB: Normal line is perpendicular to the plane between the medium.

7 0

3 years ago

Two ropes are attached to a 40-kg object. The first rope applies a force of 25 N and the second, 40 N. If the two ropes are perp

kifflom [539]

Answer:

1.2 m/s^2

Explanation:

I will ignore gravity and friction....and will choose 25 N as UP and 40 N to Left (see diagram)

Resultant force: R^2 = 25^2 + 40^2 R = sqrt(2225)=47 N

F = ma

F/m = a

47 N / 40 kg = a = 1.2 m/s^2

8 0

1 year ago

Water drips from the nozzle of a shower onto the floor 193 cm below. The drops fall at regular (equal) intervals of time, the fi

Law Incorporation [45]

Answer: 108.81 cm and 48.66 cm

Explanation:

In this, we have to make sure to keep in mind the Gravity effects on the drops. The drops will accelerate when they fall making them travel faster. This means, the velocity is not constant.

What is know:

Height (h) = 193 cm

Gravity (g) = 981 $cm/s^{2}$

Initial Velocity = 0

First, we can know how long it take to the drop to travel to the floor. It can be done with the following equation:

$x = V_{0} t + \frac{1}{2} at^{2}$ (1)

Where:

x is the distance which is 193cm

Vo is the Initial Velocity which is zero

t is the time the time it takes the drop to travel from the shower to the floor

a is the aceleration, which in this case is the gravity.

With the Initial Velocity equals zero the equations simply:

$193 cm = \frac{1}{2}gt^{2}$

To search for the time:

$t =\sqrt{\frac{2*193cm}{981cm/s^{2} } }$

t = 0.627 s

This is the time it takes a drop to fall to the floor, with this time and knowing other 3 drops have driped from the shower by this time. We can calculate how much time it takes the shower to drip each drop.

Time for Drip = t/4

Time for Drip = 0.156

This time is the difference between each drop, using the same equation we can calculate where was each drop, because now it is know how much time had each drop after being drip from the shower.

Our first is already on the floor (193 cm) with 0.627 s, The second drops have been falling for (0.627s - 0.156) 0.471 s and our third drop for (0.627s - 0.156 - 0.156) 0.315 s

We can use (1) to know how far have each drop traveled on these times. We know the Initials Velocity are 0, know we need ot know the distances.

For the second drop:

$x = \frac{1}{2} (981cm/s^{2})(0.471s)^{2}$