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Dimas [21]
3 years ago
8

Which of the following is TRUE? Group of answer choices None of the above is true. The equivalence point is where the amount of

acid equals the amount of base during any acid-base titration. An indicator is not pH sensitive. A titration curve is a plot of pH vs. the [base]/[acid] ratio. At the equivalence point, the pH is always 7.
Chemistry
1 answer:
kaheart [24]3 years ago
4 0

Answer:

TRUE: The equivalence point is where the amount of acid equals the amount of base during any acid-base titration.

Explanation:

The point on the titration curve where the number of base equivalents added equals the number of acid equivalents is the equivalence point or neutralization point.

Chemical indicators are substances that change color thanks to a chemical change, depending on the pH of the medium, and thus indicate the end point or point of equivalence of an acid-base volumetry.

A titration curve occurs by representing the measured pH as a function of the added volume of titrant, where the rapid change in pH for a given volume is observed. The inflection point of this curve is called the equivalence point and its volume indicates the volume of titrant consumed to fully react with the analyte.

In some cases, there are multiple equivalence points that are multiples of the first equivalence point, as in the valuation of a diprotic acid, which indicates that its pH value will not always be 7.

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Answer:

a=-3.37\ m/s^2

Explanation:

Given that,

A car accelerates negatively from 35m/s to 8m/s in 8s.

We need to find the car's acceleration.

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Final speed, v = 8 m/s

Time, t = 8 s

The acceleration of an object is equal to the rate of change of velocity. So,

a=\dfrac{v-u}{t}

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a=\dfrac{8-35}{8}\\\\a=-3.37\ m/s^2

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8 0
3 years ago
1.Complete the balanced neutralization equation for the reaction below:
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1. H_{2}SO_{4} + Sr(OH)_{2} ⇒ SrSO4 + 2 H2O is the balanced reaction.

2. 0.034 liters of KI will be required  completely react with 2.43 g of Cu(NO3)2.

3. 0.55 liters is the volume in L of a 0.724 M Nal solution contains0.405 mol of NaI.

4. 33.3 ml  many mL of 0.300 M NaF would be required to make a 0.0400 M solution of NaF when diluted to 250.0 mL with water

Explanation:

Balance chemical reaction of neutralization:

1. H_{2}SO_{4} + Sr(OH)_{2} ⇒ SrSO4 + 2 H2O

2. Data given:

balance chemical reaction:

2Cu(NO₃)₂(aq) + 4KI(aq) → 2CuI(aq) + I₂(s) + 4KNO₃(aq)

molarity of KI = 0.209 M

mass of Cu(NO₃)₂ = 2.43 grams

number of moles of Cu(NO₃)₂ will be calculated as:

number of moles = \frac{mass}{atomic mass of 1 mole}

atomic mass of Cu(NO₃)₂ = 187.56 grams/mole

putting the values in the equation,

number of moles= \frac{2.43}{187.56}

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2 moles of Cu(NO₃)₂ will react with 4 moles of KI

0.0129 moles will react with x moles of KI

\frac{4}{2} = \frac{x}{0.0129}

x = 0.0258

atomic mass of KI = 166.00 grams/mole

mass = 166.00 x 0.0258

        = 4.28 grams or ml is the final volume of KI

so molarity = \frac{number of moles}{volume in litres}

so molarity of KI is 0.0258 M, volume is 1 litre.

Using the formula

Minitial x Vinitial = M final Vfinal

V initial = \frac{M final Vfinal}{Minitial}

           = \frac{4.28 X 0.209}{0.0258}

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3) Data given:

molarity of NaI = 0.724

number of moles of NaI =?

Volume in litres =?

formula used:

molarity = \frac{number of moles}{volume in liters}

volume in litres = \frac{0.405}{0.724}

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4) Data given:

Initial molarity = 0.3 M

initial volume = ?

final molarity = 0.04 M

final volume diluted by = 250 ml

formula used:

M initial X Vinitial = Mfinal X V final

putting the values in the equation:

Vinitial = \frac{0.04 X 250}{0.3}

            = 33.3 ml of 0.3 M solution will be required.

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